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Harman [31]
3 years ago
14

1. A bag contains rubber bands with lengths that are normally distributed with a mean of 6 cm of length, and a standard deviatio

n of 1.5 cm. What percentage of rubber bands can be expected to be shorter than 3 cm?
Mathematics
1 answer:
romanna [79]3 years ago
4 0
Roughly 1.7 percent of the bands are shorter than 3cm. We calculate the z score of the data point in standard distribution. By definition of z score, we use score minus mean divided by standard deviation. z=(3-6)/1.5=-2. A z score of -2 corresponds to approximately 1.7%, in other words, roughly 1.7 percent of data is less than 3cm.
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Answer:

\sf   \sqrt{3}

Step-by-step explanation:

\sf =  \frac{3}{ \sqrt{3} }

\sf =  \frac{3}{ \sqrt{3} }  \times  \frac{ \sqrt{3} }{ \sqrt{3} }

\sf =  \frac{3 \sqrt{3} }{( \sqrt{3} \times  \sqrt{3})  }

\sf =  \frac{3 \sqrt{3} }{3}

\sf =  \frac{ \cancel{3} \sqrt{3} }{ \cancel3}

\sf =  \sqrt{3}

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You can do this by replacing x = -2y + 10 in second equation and solving for y then plug this value of y in first equation to find x then use these values of x and y in last equation to find zSHOW FULL ANSWER
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<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ 3/10 = 0.3

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<h3><u>✽</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

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