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Harman [31]
3 years ago
14

1. A bag contains rubber bands with lengths that are normally distributed with a mean of 6 cm of length, and a standard deviatio

n of 1.5 cm. What percentage of rubber bands can be expected to be shorter than 3 cm?
Mathematics
1 answer:
romanna [79]3 years ago
4 0
Roughly 1.7 percent of the bands are shorter than 3cm. We calculate the z score of the data point in standard distribution. By definition of z score, we use score minus mean divided by standard deviation. z=(3-6)/1.5=-2. A z score of -2 corresponds to approximately 1.7%, in other words, roughly 1.7 percent of data is less than 3cm.
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I need help working this out
Leona [35]

I think in this situation the best method would be a guess and check. You know that there are 8 dimes more than there are nickels. So just keep increasing each number by one until you reach $1.40. If there were 9 dimes and 1 nickels it would add up to $0.95. If there were 10 dimes and 2 nickels, it would add up to $1.10. If there were 11 dimes and 3 nickels, it would add up to $1.25. If there were 12 dimes and 4 nickels, it would add up to $1.40. So your answer is 12 dimes and 4 nickels.

I hope this helped!

8 0
3 years ago
Read 2 more answers
Which statements describe the cell membrane? Check all that apply.
o-na [289]

Answer:

you can use the website called "Force Calculator" it will give you the answer, just enter the mass and the acceleration <3 :) good luck

Step-by-step explanation:

8 0
3 years ago
Y2-x3 when x=2,y=4 x1+x3-y2 when x=3 y=5 x4 divide x3 x=6 please help am bad at this
Katen [24]

Answer:

8 , 5 , 5.785

Step-by-step explanation:

y^2 - x^3

first just plug in the numbers and you get

(4)^2 - (2)^3

Multiply

16-8 and this equals 8

x1 + x^3 - y^2

same pattern plug in the numbers

(3)^(1) + (3)^3 - (5)^2

multiply

3 + 27 - 25

P

E

M

D

Addition

Subtraction so do 3+27 first and you get

30 - 25 = 5

x^4 / x^3 plug it in

(6)^4 / (6)^3

multiply

1269  / 216  

divide this and you get

5.875

8 0
3 years ago
The figure of Circle A shown below has diameter PR which intersects QS at point B and the measurements shown. Calculate the foll
nata0808 [166]

The figure is an illustration of the relationship between the angles in a circle and arc

<h3>The measure of angle PSQ</h3>

From the figure, the arc PQ is subtended by the angle PAQ.

This means that:

PQ = ∠PAQ

Given that ∠PAQ = 130, it means that:

Arc PQ = 130

The measure of PSQ is then calculated using:

∠PSQ = 0.5 * Arc PQ ----- inscribed angle is half a subtended angle.

This gives

∠PSQ = 0.5 * 130

∠PSQ = 65

Hence, the measure of ∠PSQ is 65 degrees

<h3>The measure of arc QR</h3>

A semicircle measures 180 degrees.

This means that:

QR + PQ = 180

So, we have:

QR = 180 - PQ

Substitute 130 for PQ

QR = 180 - 130

QR = 50

Hence, the measure of QR is 50 degrees

<h3>The measure of arc RS</h3>

The measure of arc RS is then calculated using:

∠RPS = 0.5 * Arc RS ----- inscribed angle is half a subtended angle.

Where ∠RPS = 35

So, we have:

35 = 0.5 * Arc RS

Multiply both sides by 2

Arc RS = 70

Hence, the measure of RS is 70 degrees

<h3>The measure of angle AQS</h3>

In (a), we have:

∠PSQ = 65

This means that:

∠PSQ = ∠PSB = 65

So, we have:

∠PSB = 65

Next, calculate SBP using:

∠SBP + ∠BPS + ∠PSB = 180 ---- sum of angles in a triangle.

So, we have:

∠SBP + 35 + 65 = 180

∠SBP + 100 = 180

This gives

∠SBP = 80

The measure of AQS is then calculated using:

AQS = AQB = 180 - (180 - SBP) - (180 - PAQ)

This gives

AQS = 180 - (180 - 80) - (180 - 130)

Evaluate

AQS = 30

Hence, the measure of AQS is 30 degrees

<h3>The measure of arc PS</h3>

A semicircle measures 180 degrees.

This means that:

PS + RS = 180

This gives

PS = 180 - RS

Where RS = 70

So, we have:

PS = 180 - 70

Evaluate

PS = 110

Hence, the measure of arc PS is 110 degrees

Read more about circles and arcs at:

brainly.com/question/15096899

#SPJ1

6 0
2 years ago
WHAT ARE THE REAL SOLUTIONS FOR X IF |X|-7=7? DUE BY 11 HURRY PLEASE
lubasha [3.4K]

Answer:

x=14,-14

ive answered like 4 of your questions lol

4 0
2 years ago
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