Question

Simply 6^-1(4^-2) plz help

Answer 1

Answer:

  1/96

Step-by-step explanation:

The applicable rule of exponents is ...

  a^-b = 1/a^b

Then ...

$6^{-1}\cdot 4^{-2}=\dfrac{1}{6}\cdot\dfrac{1}{4^{2}}=\dfrac{1}{6\cdot 16}=\dfrac{1}{96}$