Simply 6^-1(4^-2) plz help

Mathematics

1 answer:

KATRIN_1 [288]3 years ago

6 0

Answer:

1/96

Step-by-step explanation:

The applicable rule of exponents is ...

a^-b = 1/a^b

Then ...

$6^{-1}\cdot 4^{-2}=\dfrac{1}{6}\cdot\dfrac{1}{4^{2}}=\dfrac{1}{6\cdot 16}=\dfrac{1}{96}$

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