Given p ≠ q ≠ 0, what is the equation of the line that passes through the points (–p, –q) and (p, q)?

2 answers:

7 0

Hey :))

(-p,-q)(p,q)slope = (q - (-q) / (p - (-p) = (q + q) / (p + p) = 2q / 2p = q/p
y = mx + b.....slope(m) = q/p(p,q)...x = p and y = qnow we sub and find b, the y intq = (q/p)(p) + bq = q + bq - q = b0 = b
so ur equation is : y = (q/p)x + 0...or just y = (q/p)x....its answer B
HOPE THIS HELPED!!! :))

DedPeter [7]3 years ago

7 0

Solution:

The equation of the line that passes through the points: <em>y</em> = q/p <em>x</em>

You might be interested in

I literally don’t get this I need the answer

Ksju [112]

Answer:

62.83 $units^{3}$

Step-by-step explanation:

The equation is V(Volume) equals π (Pi/3.14) multiplied by r(radius) squared multiplied by h(height). The way it would be written out is V=π× $r^{2}$ ×h. So when you plug in the radius (2) and the height (5) you get π× $2^{2}$ ×5 which equals 62.83185 or 62.83. I hope this helps you understand and if you need more help let me know.