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Bingel [31]
3 years ago
14

Help me with this math problem??

Mathematics
1 answer:
vlabodo [156]3 years ago
3 0

Answer:

B; 4.5 meters.

Step-by-step explanation:

Analyzing the question, we can see that 1 cm is equivalent to 1.5 meters.

Therefore, we must multiply 1.5 * 3 because the height of the sailboat in her drawing is 3 cm, and will be multiplied by 1.5 meters to find the real height.

1.5 * 3 = 4.5

Thusly, the height, in meters, of the actual boat is \boxed{{4.5\text{\:meters\:or\:B}}}.

Hope this helps! (:

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Solve similar triangles (advanced)<br> Solve for x<br> x=?
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Answer:

x = 1.2

Step-by-step explanation:

AD/AB = DE/BC (Similarity Theorem)

AD = 6 + 4 = 10

AB = 6

DE = 2

BC = x

Plug in the values

10/6 = 2/x

Cross multiply

10*x = 2*6

10x = 12

Divide both sides by 10

x = 12/10

x = 1.2

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Given that cot θ = 1/√5, what is the value of (sec²θ - cosec²θ)/(sec²θ + cosec²θ) ?
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Step-by-step explanation:

\mathsf{Given :\;\dfrac{{sec}^2\theta - co{sec}^2\theta}{{sec}^2\theta + co{sec}^2\theta}}

\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{{sec}\theta = \dfrac{1}{cos\theta}}}}

\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{co{sec}\theta = \dfrac{1}{sin\theta}}}}

\mathsf{\implies \dfrac{\dfrac{1}{cos^2\theta} - \dfrac{1}{sin^2\theta}}{\dfrac{1}{cos^2\theta} + \dfrac{1}{sin^2\theta}}}

\mathsf{\implies \dfrac{\dfrac{sin^2\theta - cos^2\theta}{sin^2\theta.cos^2\theta}}{\dfrac{sin^2\theta + cos^2\theta}{sin^2\theta.cos^2\theta}}}

\mathsf{\implies \dfrac{sin^2\theta - cos^2\theta}{sin^2\theta + cos^2\theta}}

Taking sin²θ common in both numerator & denominator, We get :

\mathsf{\implies \dfrac{sin^2\theta\left(1 - \dfrac{cos^2\theta}{sin^2\theta}\right)}{sin^2\theta\left(1 + \dfrac{cos^2\theta}{sin^2\theta}\right)}}

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\mathsf{\implies \dfrac{\dfrac{5 - 1}{5}}{\dfrac{5 + 1}{5}}}

\mathsf{\implies \dfrac{5 - 1}{5 + 1}}

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\mathsf{\implies \dfrac{2}{3}}

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π≈3.14
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