All categories

3 years ago

Solve 5/3x ≤ 10. Graph the solution

Mathematics

1 answer:

VashaNatasha [74]3 years ago

3 0

, .
........................................

You might be interested in

Please help me with this expression problem!

kkurt [141]

Answer:

=k= -2.2/6.7

= k=(.328)

Step-by-step explanation:

2.2=k+6.7/-1

=2.2×-1=6.7+k

=k= -2.2/6.7

= k=(.328)

Hey mate hope it's help you.....

4 0

2 years ago

You ate three of the eight pizza slices. You paid $9.45 as your share of the cost of the pizza. Write a one step equation to fin

Tema [17]

Answer:

Step-by-step explanation:

you ate 3

you paid $9.45 for the 3

to find the cost of the whole pizza you need to know how much each slice costs so

9.45 / 3 = $3.15 a slice

so each slice is $3.15 and there are 8 slices and you need to know how much they cost altogether so

3.15 * 8 = $25.20

7 0

3 years ago

Read 2 more answers

What is the cross-sectional area of a cement pipe 2 in. thick with an inner diameter of 5 ft? Use pie 3.14.

Paul [167]

Answer:

1.60 $ft^{2}$

Step-by-step explanation:

Assuming that this is a cylindrical pipe, the area can be determined by applying the formula for calculating the area of a circle.

i.e Area = $\pi$ $r^{2}$

So that,

for the inner part of the pipe,

r = $\frac{diameter}{2}$

= $\frac{5}{2}$

= 2.5 feet

Area of the inner part of the pipe = $\pi$ $r^{2}$

= 3.14 x $(2.5)^{2}$

= 19.625

Are of the inner part of the pipe is 19.63 $ft^{2}$ .

Total diameter of the pipe = 5 + 0.2

= 5.2 feet

r = $\frac{5.2}{2}$

= 2.6 feet

Area of the pipe = $\pi$ $r^{2}$

= 3.14 x $(2.6)^{2}$

= 21.2264

Area of the pipe is 21.23 $ft^{2}$ .

Thus the cross sectional area = Area of the pipe - Area of the inner part of the pipe

= 21.2264 - 19.625

= 1.6014

The cross sectional area of the cement pipe is 1.60 $ft^{2}$ .

6 0

2 years ago

the area of a rectangle hall is the same as the area of a square field of side 56 m. if the lenght of hall is 112m. find its bre

Semmy [17]

Step-by-step explanation:

please subscribe to my mom channel please

7 0

3 years ago

Sam has $440 in $20, $10, and $5 dollar bills. The number of twenties, tens and fives are consecutive integers in this order. Ho

Ludmilka [50]

Answer: There are 12 bills for $20, 13 bills for $10 and 14 bills for $5.

Step-by-step explanation:

Let the number of twenties be x

Let the number of tens be x+1

Let the number of fives be x+2

Amount from twenties will be given as

$20\times x=20x$

Amount from tens will be given as

$10\times (x+1)=10x+10$

Amount from fives will be given as

$5\times (x+2)=5x+10$

According to question,

$20x+10x+10+5x+10=440\\\\35x+20=440\\\\35x=440-20\\\\35x=420\\\\x=\frac{420}{35}\\\\x=12$

So, there are 12 bills for $20, 13 bills for $10 and 14 bills for $5.

6 0

3 years ago