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german
3 years ago
15

A pattern is made by toothpick squares. Select the series that represents the number of toothpicks added to a picture to get the

next picture to the right. Pretend the first picture has no toothpicks.
4 + 12 + 24 + 40 + ...; rule is an = 2(n2 + n)
1 + 2 + 3 + 4 + ...; rule is an = n
1 + 4 + 9 + 16 + ...; rule is an = n2
4 + 8 + 12 + 16 + ...; rule is an = 4n

The first one has one square the next one has 4 the next one has 9 and the last one has 16
Mathematics
1 answer:
lorasvet [3.4K]3 years ago
4 0
The answer is, 4 + 8 + 12 + 16 ... rule is 4n.

Explanation:

one square has 4 toothpicks, then you added 4 picks (because you started with zero squares).

4 squares have 12 toothpicks, then you added 8 toothpicks to pass from one square to 4 squeres.

If you follow that reasoing you get to realize that the additions are 4, 8, 12, 16.
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The standard form for this parabola is x = a(y-k)^2 + h because this is a sideways-opening parabola. Our h and k values for the vertex are (-4, -1). And it goes through (2,0). We just need to solve for the a. Filling in accordingly, 2 = a(0+1)^2-4 so 2 = a - 4. a = 6. A above.

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Answer:

The product is:

\left[\begin{array}{cc}15 & 14\\-1 & 9\end{array}\right]

Step-by-step explanation:

For this problem you need to multiply the first row only for the two first column of the others matrix and get the desired result:

\left[\begin{array}{ccc}1&3&1\\-2&1&0\end{array}\right] \times \left[\begin{array}{cc}2&-2\\3&5\\4&1\end{array}\right]

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So the value of the element in the position a_{11} is 15

1 \times -2 + 3 \times 5 + 1 \times 1 = 14

So the value of the element in the position a_{12} is 14

Then with these two values you can determinate the result matrix.

\left[\begin{array}{cc}15 & 14\\-1 & 9\end{array}\right]

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44

Step-by-step explanation:

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