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2 years ago

List all the factors of the number 30.

Mathematics

1 answer:

vekshin12 years ago

5 0

Answer:

A. 1 2 3 5 6 10 15 30. hope this helps

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How many 330ml bottles could you completely fill with 4 litres of water

Neko [114]

Answer:

12.1212-repeating

Step-by-step explanation:

Milliliters are 1000 times smaller (Larger in number, smaller in size). So when you calculate 4 liters times 1000, you would get 4000 milliliters. Then you would divide the 4000 by 330, and then you would get 12.121212-Repeating decimal.

7 0

2 years ago

7 over 2 as a mixed number

ivanzaharov [21]

Answer:

3 1/2

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Write three equations whose solution is x=3.5

My name is Ann [436]

Answer:

1. 2x + 23 = 30

2. 3x + 19.5 = 30

3. (10x - 20)/ 5 = 3

Explanation:

Work backward:

1. 2x + 23 = 30

Start:

x = 3.5

Multiply the equation by 2:

2x = 2 (3.5)
2x = 7

Subtract 30 from both sides

2x - 30 = 7 - 30
2x - 30 = -23

Add 23 and 30 to both sides:

2x + 23 = 30

2. 3x + 19.5 = 30

Start:

x = 3.5

Add 6.5 to both sides:

x + 6.5 = 10

Multiply by 3:

3(x + 6.5) = 30

Distributive property:

3x + 19.5 = 30

3. (10x - 20)/ 5 = 3

Start:

x=3.5

Multiply by 10:

10x = 35

Subtract 20:

10x - 20 = 15

Divide by 5:

(10x - 20)/ 5 = 15/5

(10x - 20) / 5 = 3

3 0

3 years ago

In the △ABC, the height AN = 24 in, BN = 18 in, AC = 40 in. Find AB and BC. Consider all possible cases. Case 1 : N∈BC, AB = __,

aivan3 [116]

Answer:

Case 1:

$AB = 30$

$BC = 50$

Case 2:

$AB = 15.9$

$BC = 36.7$

Case 3: Not possible

Step-by-step explanation:

Given

See attachment for illustration of each case

Required

Find AB and BC

Case 1:

Using Pythagoras theorem in ANB, we have:

$AB^2 = AN^2 + BN^2$

This gives:

$AB^2 = 24^2 + 18^2$

$AB^2 = 576 + 324$

$AB^2 = 900$

Take square roots of both sides

$AB = \sqrt{900$

$AB = 30$

To calculate BC, we consider ANC, where:

$AC^2 = AN^2 + NC^2$

$40^2 = 24^2 + NC^2$

$1600 = 576 + NC^2$

Collect like terms

$NC^2 = 1600 - 576$

$NC^2 = 1024$

Take square roots

$NC = \sqrt{1024$

$NC = 32$

So:

$BC = NC + BN$

$BC = 32 + 18$

$BC = 50$

Case 2:

Using Pythagoras theorem in ANB, we have:

$AN^2 = AB^2 + BN^2$

This gives:

$24^2 = AB^2 + 18^2$

$576 = AB^2 + 324$

Collect like terms

$AB^2 = 576 - 324$

$AB^2 = 252$

Take square roots of both sides

$AB = \sqrt{252$

$AB = 15.9$

To calculate BC, we consider ABC, where:

$AC^2 = AB^2 + BC^2$

$40^2 = 252 + BC^2$

$1600 = 252 + BC^2$

Collect like terms

$BC^2 = 1600 - 252$

$BC^2 = 1348$

Take square roots

$BC = \sqrt{1348$

$BC = 36.7$

Case 3:

This is not possible because in ANC

The hypotenuse AN (24) is less than AC (40)

3 0

2 years ago

You will not be given credit for your answer if you do not include your equation! Your family took a trip to Florida. After the

bazaltina [42]

Answer:

80 mph

Step-by-step explanation:

720÷9=80

hope this helps!!!

3 0

3 years ago