You would just do 5.7-8.1, which is -3.6 degrees Celcius. Hope I helped!
Answer:
The coordinates of the circumcenter of this triangle are (3,2)
Step-by-step explanation:
we know that
The circumcenter is the point where the perpendicular bisectors of a triangle intersect
we have the coordinates

step 1
Find the midpoint AB
The formula to calculate the midpoint between two points is equal to

substitute the values


step 2
Find the equation of the line perpendicular to the segment AB that passes through the point (-2,2)
Is a horizontal line (parallel to the x-axis)
-----> equation A
step 3
Find the midpoint BC
The formula to calculate the midpoint between two points is equal to

substitute the values


step 4
Find the equation of the line perpendicular to the segment BC that passes through the point (3,-1)
Is a vertical line (parallel to the y-axis)
-----> equation B
step 5
Find the circumcenter
The circumcenter is the intersection point between the equation A and equation B
-----> equation A
-----> equation B
The intersection point is (3,2)
therefore
The coordinates of the circumcenter of this triangle are (3,2)
The answer is 7 because it goes 10th 100th and the thirty one is thousands
56.3 is your answer in simplest from
Answer:
The area of △MNP is one fourth of the area of △ABC.
Step-by-step explanation:
It is given that the points M, N, and P are the midpoints of sides AC, BC and AB respectively. It means AC, BC and AB are median of the triangle ABC.
Median divides the area of a triangle in two equal parts.
Since the points M, N, and P are the midpoints of sides AC, BC and AB respectively, therefore MN, NP and MP are midsegments of the triangle.
Midsegments are the line segment which are connecting the midpoints of tro sides and parallel to third side. According to midpoint theorem the length of midsegment is half of length of third side.
Since MN, NP and MP are midsegments of the triangle, therefore the length of these sides are half of AB, AC and BC respectively. In triangle ABC and MNP corresponding side are proportional.



By the property of similar triangles,



Hence proved.