Question

Help Please! <3

Answer 1

For this case we have the following system of equations:

$12x + 6y = 120\\4x + y = 30$

We must solve the system by the method of elimination. To do this we multiply the second equation by -3, then:

$12x + 6y = 120\\-12x-3y = -90$

We add both equations:

$12x-12x + 6y-3y = 120-90\\3y = 30\\y = \frac {30} {3}\\y = 10$

We find the value of "x":

$4x + y = 304x + 10 = 30\\4x = 30-10\\4x = 20\\x = \frac {20} {4}\\x = 5$

Thus, the solution of the system is:

$(x, y) :( 5,10)$

We verify:

$12 (5) +6 (10) = 120\\60 + 60 = 120\\120 = 120$

Is fulfilled!

$4 (5) + 10 = 30\\20 + 10 = 30\\30 = 30$

Is fulfilled!

Answer:

$(x, y) :( 5,10)$