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2 years ago

Please help me!!!!!!!!!!!!! I'll give brainleist !!

2 answers:

7 0

If your looking for the answer, this question is invalid. However, if the question is asking for the function equation, the answer is y=3x-2

Nataliya [291]2 years ago

6 0

Let "a" represent Alex' age. Translating the given sentence into symbols,

a = 3(a-2). Thus, a = 3a - 6, or 6 = 2a, or a = 3.

Alex is 3 years old now. (Answer)

Check:

2 years ago he was (3-2), or 1, year old. three times that does equal 3.

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Is n+4 equal to 8(n - 4)

weqwewe [10]

No, n+4=4n an 8(n-4)=32n

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3 years ago

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Lisa is cutting a 14-inch piece of paper into 0.4-inch strips. How many strips of paper will she have when she is finished?

QveST [7]

35 pieces since 14/.4 is 35.

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3 years ago

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Find the area of sector DEF (show work please)

Whitepunk [10]

Answer:

240

Step-by-step explanation:

360-120=240

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3 years ago

PLEASE ANSWER Answer Choices: 1# 28.26 2# 15.7 3# 12.56 4# 14.13

Setler [38]

Answer: 2

Step-by-step explanation: because it timed the seconde one so that is why its 2

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3 years ago

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Annie is framing a photo with a length of 6 inches and a width of 4 inches. The distance from the edge of the photo to the edge

Ede4ka [16]

Answer:

Part a) The quadratic function is $4x^{2} +20x-39=0$

Part b) The value of x is $1.5\ in$

Part c) The photo and frame together are $7\ in$ wide

Step-by-step explanation:

Part a) Write a quadratic function to find the distance from the edge of the photo to the edge of the frame

Let

x----> the distance from the edge of the photo to the edge of the frame

we know that

$(6+2x)(4+2x)=63\\24+12x+8x+4x^{2}=63\\ 4x^{2} +20x+24-63=0\\4x^{2} +20x-39=0$

Part b) What is the value of x?

Solve the quadratic equation $4x^{2} +20x-39=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem

we have

$4x^{2} +20x-39=0$

$a=4\\b=20\\c=-39$

substitute in the formula

$x=\frac{-20(+/-)\sqrt{20^{2}-4(4)(-39)}} {2(4)}$

$x=\frac{-20(+/-)\sqrt{1,024}} {8}$

$x=\frac{-20(+/-)32} {8}$

$x=\frac{-20(+)32} {8}=1.5\ in$ -----> the solution

$x=\frac{-20(-)32} {8}=-6.5\ in$

Part c) How wide are the photo and frame together?

$(4+2x)=4+2(1.5)=7\ in$

5 0

3 years ago