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jeyben [28]
3 years ago
9

A swimming pool at a park measures 9.75 meters by 7.2 meters the area of the playground is one and half times that of the swimmi

ng pool. Find total area of the swimming pool and the playground
Mathematics
1 answer:
ElenaW [278]3 years ago
8 0
9.75 x 7.2 = 70.2
Swimming Pool Area: 70.2
The Park Area: 70.2 x 1.5 = 105.3
Total Area of both Swimming Pool & Park area: 70.2 + 105.3 = 175.5
Final Answer: 175.5
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Answer:

Put the numbers in order then find the number that appears the most which is 12.

Step-by-step explanation:

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Simplify the radical completely.
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Answer:

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Step-by-step explanation:

But basically, one by one you try moving the terms out of the radical.

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Hope that helps!

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2 years ago
Connie keeps her sports card collection in a 54-page book. Each page has 9 slots for cards. Football cards take up the first 18
jeyben [28]

Answer:

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Step-by-step explanation:

4 0
3 years ago
A lighthouse is located on a small island 5 km away from the nearest point P on a straight shoreline and its light makes seven r
Vaselesa [24]

Answer:

Light is moving at the speed = 77.78 km/min

Step-by-step explanation:

Given:

Distance between island and point P = 5 km

Moving along the the shoreline when it is 1 km from P.

So, x = 1

From the above statement light makes seven revolutions per minute.

Therefore,              

\frac{d\theta}{dt}=\frac{7\times 2\pi\ rad}{1\ min}  = 14\pi\ rad/min  

Solution:

From the given figure.

tan\theta=\frac{x}{5}

Substitute x = 1

tan\theta=\frac{1}{5}  -------------------(1)

Now, first we differentiate both side with respect to t.

\frac{d(tan\theta)}{dt} = \frac{d}{dt}.(\frac{x}{3})

Using chain rule.

\frac{d(tan\theta)}{dt}.\frac{d\theta}{dt}  = (\frac{1}{5})\frac{dx}{dt}

sec^{2} \theta.\frac{d\theta}{dt} = \frac{1}{5}.\frac{dx}{dt}

(1+tan^{2} \theta).\frac{d\theta}{dt} = \frac{1}{5}.\frac{dx}{dt}

Substitute tan\theta=\frac{1}{5} from equation 1.

(1+(\frac{1}{3})^{2} ).\frac{d\theta}{dt} = \frac{1}{5}.\frac{dx}{dt}

(1+\frac{1}{9}).\frac{d\theta}{dt} = \frac{1}{5}.\frac{dx}{dt}

Substitute \frac{d\theta}{dt}=14\pi

\frac{10}{9}.14\pi  = \frac{1}{5}.\frac{dx}{dt}

Applying cross multiplication rule.

\frac{dx}{dt}= \frac{700\pi }{9}

\frac{dx}{dt}= 77.78\pi

Therefore, light is moving along the shore at the speed of 77.78 km/min

6 0
3 years ago
Carla is following a recipe that calls for a cinnamon-sugar mixture that is 5% cinnamon.
Dahasolnce [82]

Answer:

Step-by-step explanation:

It's a proportion rather than an equation that you might be more accustomed to.

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2 * 0.95/0.05 = x

x = 38 grams of sugar should be added to the 2 grams of cinnamon.

There's another way to do it.

2/0.05 = (x + 2)/1      Cross multiply

2*1 = 0.05x + 0.1       Subtract 0.1 from both sides

1.9 = 0.05x

1.9/0.05 = x

x = 38

Which ever way you understand better is the answer. 100 / 100% is 1

3 0
3 years ago
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