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RUDIKE [14]
2 years ago
5

Find the sum of the first 150 terms of the arithmetic series: 4, 5, 6, 7, 8, … 7,345 11,775 13,322 15,654

Mathematics
1 answer:
Tanya [424]2 years ago
7 0
4, 5, 6, 7, 8, . . .
a = 4, d = 5 - 4 = 1, n = 150
Sn = n/2[2a + (n - 1)d]
S(150) = 150/2[2(4) + (150 - 1)1] = 75[8 + 149] = 75(157) = 11,775
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konstantin123 [22]
Answer:  " 4x + 2xy - 7pq " .
___________________________________
Explanation:
___________________________________
Given:  
" <span>4x - 7xy + 9xy - 7pq " ;  Simplify the expression;
___________________________________
  Combine the "like terms:
___________________________________
       -7xy + 9xy = 2xy ;
___________________________________
Now, rerewrite the expression, substituting the "-7xy + 9xy";  with " + 2xy" ;
___________________________________
   </span>→ " 4x + 2xy - 7pq " .
<span>___________________________________


</span>
4 0
3 years ago
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