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2 years ago

I need help on this help help I’ll give out some money

Mathematics

1 answer:

frozen [14]2 years ago

6 0

<h3>a) Never</h3>

{All angles of a rectangle are right}

<h3>b) Always</h3>

{all sides of a rhombus are the same, 4×13=52}

<h3>c) Always</h3>

{oposite angles of a paralleogram are congruent}

<h3>d) Never</h3>

{parallel sides has the same slope}

<h3>e) Always</h3>

{square has all sides of the same length, so it is rhombus}

<h3>f) Sometimes</h3>

{Only if it has angles of 90°}

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Kevin is three years older than Daniel. Two years ago, Kevin was 4 times as old as Daniel.

GarryVolchara [31]

Answer:

I believe that Kevin is 6 years old now.

Step-by-step explanation:

I used the guess and check method to figure this out.

First, I began by making Daniel 1 years old, two years ago. Kevin was 4 times as old as Daniel two years ago, so he would be 4 at the time. Now, Daniel would be 3 and Kevin would be 6 years old. The statement that Kevin is three years older than Daniel would confirm this, because 6-3=3. Hope this helps, this is my first time answering:)

3 0

3 years ago

A university has 750 female students and 2250 male students. Thirty per cent of female students study chemistry and 60% of male

UNO [17]

Answer:

1/7 or 14.3%

Step-by-step explanation:

30% of 750 = 225 (females who study chemistry)

60% of 2250 = 1350 (males who study chemistry)

1575 = total students studying chemistry

P (female chemistry student) = 225/1575 = 1/7 (simplified)

1/7 = 14.3%

7 0

2 years ago

Y=4x-6 and passes through point 8,12

umka2103 [35]

Answer:

Slope of required line if both lines are parallel: y=4x-20

Slope of required line if both lines are perpendicular: y=-1/4x+14

Step-by-step explanation:

We need to find equation of line while we are given another line having equation y=4x-6 and passes through point (8,12)

<u><em>Note: Since it is not given if the required line is parallel or perpendicular to the given line. I will solve for both cases.</em></u>

If Both lines are parallel the equation of new line will be:

We need to find slope and y-intercept to write equation of new line.

When lines are parallel there slopes are same

So, slope of given line y=4x-6 is 4 (Compare with general equation y=mx+b, m is slope so m=4)

Slope of new line is: m=4

Now finding y-intercept

Using slope m=4 and point (8,12) we can find y-intercept

$y=mx+b\\12=4(8)+b\\12=32+b\\b=12-32\\b=-20$

y-intercept of new line is: b=-20

Equation of required line having slope m=4 and y-intercept b=-20 is

$y=mx+b\\y=4x-20$

If Both lines are perpendicular the equation of new line will be:

We need to find slope and y-intercept to write equation of new line.

When lines are perpendicular there slopes are opposite of each other

So, slope of given line y=4x-6 is 4 (Compare with general equation y=mx+b, m is slope so m=4)

Slope of new line is: m=-1/4

Now finding y-intercept

Using slope m=-1/4 and point (8,12) we can find y-intercept

$y=mx+b\\12=-\frac{1}{4} (8)+b\\12=-2+b\\b=12+2\\b=14$

y-intercept of new line is: b=14

Equation of required line having slope m=-1/4 and y-intercept b=14 is

$y=mx+b\\y=-\frac{1}{4} x+14$

8 0

2 years ago

Solve pls brainliest

Shtirlitz [24]

Answer:

1.8 or 1 4/5 should be the answer!

8 0

2 years ago

Read 2 more answers

Given an actual demand of 64, a previous forecast of 59, and an of .3, what would the forecast for the next period be using simp

BartSMP [9]

Answer: 60.5

Step-by-step explanation:

The forecast for the next period using the simple exponential smoothing method is given by:

$D\times \alpha+F(1-\alpha)$ , where D= actual demand for the recent period, $\alpha=$ smoothing factor, F= forecast for the recent period .

Given: D= 64, $\alpha=0.34$ , F= 59

The forecast for the next period = $64\times0.3+59(1-0.3)$

$\\\\= 64\times0.3+59\times0.7\\\\=19.2+41.3\\\\=60.5$

Hence, the forecast for the next period = 60.5

5 0

3 years ago