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4 years ago

7

I need the equation of the line in the graph

1 answer:

SVEN [57.7K]4 years ago

6 0

0,0 and 5,4
Now subtract

m=4/5

y=4/5x

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A rectangular field is

mojhsa [17]

350x300=105000m squared
1km=1000m
So, 105000=105km squared

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3 years ago

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Translate the sentence into a formula. The perimeter of a square equals four times the length of a side

alekssr [168]

Answer:

Let Perimeter of Square be P

Let Length of Side be S

P = 4 x S

Step-by-step explanation:

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3 years ago

Hey can anyone help me with this question

Tatiana [17]

Answer:

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3 years ago

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g A milling process has an upper specification of 1.68 millimeters and a lower specification of 1.52 millimeters. A sample of pa

adoni [48]

Complete Question

A milling process has an upper specification of 1.68 millimeters and a lower specification of 1.52 millimeters. A sample of parts had a mean of 1.6 millimeters with a standard deviation of 0.03 millimeters. what standard deviation will be needed to achieve a process capability index f 2.0?

Answer:

The value required is $\sigma = 0.0133$

Step-by-step explanation:

From the question we are told that

The upper specification is $USL = 1.68 \ mm$

The lower specification is $LSL = 1.52 \ mm$

The sample mean is $\mu = 1.6 \ mm$

The standard deviation is $\sigma = 0.03 \ mm$

Generally the capability index in mathematically represented as

$Cpk = min[ \frac{USL - \mu }{ 3 * \sigma } , \frac{\mu - LSL }{ 3 * \sigma } ]$

Now what min means is that the value of CPk is the minimum between the value is the bracket

substituting value given in the question

$Cpk = min[ \frac{1.68 - 1.6 }{ 3 * 0.03 } , \frac{1.60 - 1.52 }{ 3 * 0.03} ]$

=> $Cpk = min[ 0.88 , 0.88 ]$

So

$Cpk = 0.88$

Now from the question we are asked to evaluated the value of standard deviation that will produce a capability index of 2

Now let assuming that

$\frac{\mu - LSL }{ 3 * \sigma } = 2$

So

$\frac{ 1.60 - 1.52 }{ 3 * \sigma } = 2$

=> $0.08 = 6 \sigma$

=> $\sigma = 0.0133$

So

$\frac{ 1.68 - 1.60 }{ 3 * 0.0133 }$

=> $2$

Hence

$Cpk = min[ 2, 2 ]$

So

$Cpk = 2$

So $\sigma = 0.0133$ is the value of standard deviation required

3 0

3 years ago

John buys a water tank from a company that likes to use exponents as dimensions. The tank he buys has the dimensions b^2 by b^4

Novay_Z [31]

Answer: $b^7*c^3$

Step-by-step explanation:

Based on the information provided, you know that the dimensions of the water tank John buys are:

$b^2*b^4*bc^3$

Then, in order to find the expression that represents the volume of the water tank, you need to multiply those dimensions.

You must remember the Product of powers property, which states that:

$(a^m)(a^n)=a^{(m+n)}$

Therefore, applying this property, you get that the expression that represents the volume of the water tank is:

$b^2*b^4*bc^3=b^{(2+4+1)}+c^3=b^7*c^3$

4 0

3 years ago