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2 years ago

4.05 x 10^-2 Standard Form

Mathematics

1 answer:

defon2 years ago

5 0

Answer:

0.0405

Step-by-step explanation:

10^-2 is the same as 1/100, so if you multiply 4.05 x 1/100, you get 0.0405.

Another way to think about it is by looking at the exponent -2. You need to move the decimal point 2 spaces to the left -- and add zeroes to any spaces that don't already have numbers.

So if you start with 4.05, and move the decimal one space to the left, you get 0.405, and then you move it one more space, and you get 0.0405.

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If logx27 + logy4 =5<br>and logx27 - logy4 =1<br>find x and y

Elanso [62]

Answer:

Hello,

I have reply too quick in comments (sorry)

Step-by-step explanation:

$\left\{\begin{array}{ccc}log_x (27)+log_y (4)=5\\log_x (27)-log_y (4)=1\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}2*log_x (27)=6\\2*log_y (4)=4\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}log_x (27)=3\\log_y (4)=2\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}x^{log_x (27)}=x^3\\y^{log_y (4)}=y^2\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}27=x^3\\4=y^2\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}x=3\\y=2\\\end{array}\right.\\\\$

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2 years ago

What is the resulting equation when the expression for y in the second equation is substituted into the first equation? 3x y = 1

Natali5045456 [20]

After putting the value of y from the second equation to the first equation, the resultant equation is $x=5$ .

GIven:

The equations are:

$3x + y = 1\\
y = 6 - 4x$

It is required to put the value of y from second equation to the first equation.

<h3>How to solve equations?</h3>

The value of y from the second equation is,

$
y = 6 - 4x$

Now, put this value of y in the first equation as,

$3x + y = 1\\
3x+(6 - 4x)=1\\
3x+6-4x=1\\
-x=-5\\
x=5$

Therefore, after putting the value of y from the second equation to the first equation, the resultant equation is $x=5$ .

For more details about equations, refer to the link:

brainly.com/question/2263981

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