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AlexFokin [52]
3 years ago
15

4.05 x 10^-2 Standard Form

Mathematics
1 answer:
defon3 years ago
5 0

Answer:

0.0405

Step-by-step explanation:

10^-2 is the same as 1/100, so if you multiply 4.05 x 1/100, you get 0.0405.

Another way to think about it is by looking at the exponent -2.  You need to move the decimal point 2 spaces to the left -- and add zeroes to any spaces that don't already have numbers.

So if you start with 4.05, and move the decimal one space to the left, you get 0.405, and then you move it one more space, and you get 0.0405.

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14/126 in simplest terms
Vinil7 [7]

Answer:

1/9

Hope it helps yah (◕ᴗ◕✿)

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2 years ago
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(A) it takes 55 pounds of seed to completely plant a 9-acre field. How many pounds of seed are needed per acre?
adell [148]
A: 55 / 9 = 6.11 lbs. of seed (rounded)

B: 37 / 7 = $5.28 per hour (rounded)
7 0
3 years ago
If (x) = -54 - 4 and g(x) = -3x - 2. find (f - g)(x).
Sholpan [36]

Set up the composite result function.

f

(

g

(

x

)

)

Evaluate

f

(

g

(

x

)

)

by substituting in the value of

g

into

f

.

4

(

x

−

2

)

Apply the distributive property.

f

(

x

−

2

)

=

4

x

+

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⋅

−

2

Multiply

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by

−

2

.

f

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Step-by-step explanation:

4 0
4 years ago
EMERGENCY!!!!!!!!!!!!!!
BARSIC [14]

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Step-by-step explanation:

4 0
3 years ago
What is the range of the following function:<br> y = 2(5^x) - 1
Orlov [11]
<h2>Hello!</h2>

The answer is:

The range of the function is:

Range: y>2

or

Range: (2,∞+)

<h2>Why?</h2>

To calculate the range of the following function (exponential function) we need to perform the following steps:

First: Find the value of "x"

So, finding "x" we have:

y=2(5^{x}-1)\\\frac{y}{2}=5^{x}-1\\\\\frac{y}{2}-1=5^{x}\\\\Log_{5}(\frac{y}{2}-1)=Log_5(5^{x})\\\\x=Log_{5}(\frac{y}{2}-1)

Second: Interpret the restriction of the function:

Since we are working with logarithms, we know that the only restriction that we found is that the logarithmic functions exist only from 0 to the possitive infinite without considering the number 1.

So, we can see that if the variable "x" is a real number, "y" must be greater than 2 because if it's equal to 2 the expression inside the logarithm will tend to 0, and since the logarithm of 0 does not exist in the real numbers, the variable "x" would not be equal to a real number.

Hence, the range of the function is:

Range: y>2

or

Range: (2,∞+)

Note: I have attached a picture (the graph of the function) for better understanding.

Have a nice day!

5 0
3 years ago
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