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AfilCa [17]
4 years ago
12

In the​ 1970s, due to world​ events, there was a gasoline shortage in the United States. There were often long lines of cars wai

ting at gas stations. Part​ A: If there were 41 cars in a line that stretched 388 ​feet, what is the average car​ length? Assume that the cars are lined up​ bumper-to-bumper. Round your answer to the nearest tenth of a foot.
Mathematics
1 answer:
andrezito [222]4 years ago
7 0

Answer:

Part A: The average car length is 9.1 feet to the nearest tenth foot

Part B: The line would be 9100 feet to contained 1000 cars

Step-by-step explanation:

* Lets explain how to solve the problem

# Part A:

- There were 62 cars in a line that stretched 567 feet

- The cars are lined up bumper-to-bumper

- That means there is no empty spaces between the cars

* To find the average length of the car we will divide the length of

 the line by the numbers of the cars

∵ The average car length = length of the line/number of cars

∵ The length of the line is 567 feet

∵ The numbers of the cars is 62 cars

∴ The average car length = 567/62 = 9.1 feet

* The average car length is 9.1 feet to the nearest tenth foot

# Part B:

- There are 1000 cars

- We need to find the length of line which contained the cars

∵ The average car length = length of the line/number of cars

∵ The average of car length is 9.1 feet

∵ The number of the cars is 1000 cars

∴ 9.1 = length of the line/1000

- Multiply both sides by 1000

∴ The length of the line = 9.1 × 1000 = 9100 feet

∴ The line would be 9100 feet to contained 1000 cars

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5.2 years

Step-by-step explanation:

Applying

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Where A = amount, P = principle, R = rate, n = time.

From the question,

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Substitute these values into equation 1 and solve for n

149.18 = 100(1+8/100)ⁿ

149.18/100 = (1+8/100)ⁿ

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n = 0.1737/0.0334

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3 years ago
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Answer:

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Answer:

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Answer:

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