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garri49 [273]
3 years ago
11

ILL MARK BRAINLIEST ASAP IF CORRECT Write the equation of the quadratic function with roots -9 and and -3 and a vertex at (-6, -

1).
Mathematics
1 answer:
Oduvanchick [21]3 years ago
8 0

Answer:

see explanation

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h. k) are the coordinates of the vertex and a is a multiplier

here (h, k) = (- 6, - 1), thus

y = a(x + 6)² - 1

To find a substitute one of the roots into the equation

Using (- 3, 0), then

0 = a(- 3 +6)² - 1

0 = 9a - 1 ( add 1 to both sides )

1 = 9a ( divide both sides by 9 )

a = \frac{1}{9}, thus

y = \frac{1}{9}(x + 6)² - 1 ← in vertex form

Expand factor and simplify

y = \frac{1}{9} (x² + 12x + 36) - 1 ← distribute

y = \frac{1}{9} x² + \frac{4}{3} x + 4 - 1

  = \frac{1}{9} x² + \frac{4}{3} x + 3 ← in standard form

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I desperately need this question answered. See attached image thanks so much
Dahasolnce [82]

For this case we must follow the steps below:

step 1:

We place each of the given points on a coordinate axis

Step 2:

We join the AC points (represented by the orange line)

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It is observed that the resulting figure after placing the 4 points on a coordinate axis, turns out to be a rhombus.

In addition, the blue and orange lines turn out to be perpendicular, that is, they have an angle of 90 degrees between them. This can be verified by finding the slopes of each of the two straight lines (blue and orange), which must be opposite reciprocal, that is, they comply: m1 * m2 = -1

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Answer:

See attached image

Option D

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