2 years ago

Can someone help me with this question please

1 answer:

8 0

Start with the given equation.

P1V1=P2V2

To solve for P2, move anything else on that side to the other side so that P2 is alone.

P1V1=P2V2
P2=P1V1/V2

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jane lives 1 3/8 miles from the airport. She drove from her house to the airport and back 2 times. How far did Jane drive? Move

Ket [755]

Answer:

$5\frac{1}{2}\ mi$

Step-by-step explanation:

we know that

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She drove from her house to the airport and back 2 times

Multiply the distance from her house to the airport by 4

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2 years ago

If cos(2/3x+20)°=sin(2x−10)°, find the acute angles of the corresponding right triangle.

adell [148]

Answer:

A = 40°

B = 50°

Step-by-step explanation:

If cos A = sin B, then A + B = 90

So, 2x/3 + 20 + 2x - 10 = 90

2x + 60 + 6x - 30 = 270

8x + 30 = 270

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2 years ago

Find the surface area of each figure round your answers to the nearest hundredth if necessary

Wewaii [24]

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Step-by-step explanation:

The area of each of the triangles with their base on the 10 km side is $A=\frac{1}{2}(10)(13.4)$ , so their combined area is $(10)(13.4)=134$ .

The area of each of the triangles with their base on the 12 km side is $\frac{1}{2}(12)(13)$ , so their combined area is $(12)(13)=156$ .

The area of the bottom rectangular face is $10(12)=120$ .

So, the total surface area is $120+156+134=\boxed{410 \text{ km}^{2}}$

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1 year ago