28 i think i just guessed don't trust this answer.
Answer:
![(9 - 4) \\ ( {3}^{2} - {2}^{2}) \\ (3 - 2)(3 + 2) \\ 1 \times 5 = 5](https://tex.z-dn.net/?f=%289%20-%204%29%20%5C%5C%20%28%20%7B3%7D%5E%7B2%7D%20%20-%20%20%7B2%7D%5E%7B2%7D%29%20%5C%5C%20%283%20-%202%29%283%20%2B%202%29%20%5C%5C%201%20%5Ctimes%205%20%3D%205%20)
<em>hope</em><em> </em><em>this</em><em> </em><em>helps</em><em> </em><em>you</em><em>.</em>
PH ranges from 0 to 14, with 7 being neutral. pHs less than 7 are acidic while pHs greater than 7 are alkaline. ANSWER: false
Answer:
1.5 in
Step-by-step explanation:
Let x be the width of the frame.
Side of print=10 in
Area of frame=69 square in
We have to find the width of the frame.
Side of frame=10+x+x=10+2x
Area of square=![(side)^2](https://tex.z-dn.net/?f=%28side%29%5E2)
By using the formula
Area of print=![10\times 10=100in^2](https://tex.z-dn.net/?f=10%5Ctimes%2010%3D100in%5E2)
Area of frame with print=![(10+2x)^2](https://tex.z-dn.net/?f=%2810%2B2x%29%5E2)
Area of frame=Area of frame with print-Area of print
![69=(10+2x)^2-100](https://tex.z-dn.net/?f=69%3D%2810%2B2x%29%5E2-100)
![(10+2x)^2=69+100=169](https://tex.z-dn.net/?f=%2810%2B2x%29%5E2%3D69%2B100%3D169)
![(10+2x)=\sqrt{169}=\pm 13](https://tex.z-dn.net/?f=%2810%2B2x%29%3D%5Csqrt%7B169%7D%3D%5Cpm%2013)
![10+2x=13](https://tex.z-dn.net/?f=10%2B2x%3D13)
Because Side is always positive.
![2x=13-10=3](https://tex.z-dn.net/?f=2x%3D13-10%3D3)
![x=\frac{3}{2}=1.5](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B3%7D%7B2%7D%3D1.5)
Hence, width of frame=1.5 in