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ANTONII [103]
3 years ago
15

Tamara is a real estate agent and makes 5% commission on her total sales. She sells a home A) $17

Mathematics
2 answers:
Cerrena [4.2K]3 years ago
6 0
The answer is 350,000 * 0.05, or $17500. The answer is D.
Ludmilka [50]3 years ago
6 0
350000*.05(5%)=$17,500

Hope that helps
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A circle has a circumference of 153.86 units. What is the radius of the circle?
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Radius = 24.49

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Curtis decided to go on a road trip to Canada. On the first day of his trip, he drove for 14 hours and traveled 840 miles. At wh
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A

Step-by-step explanation:

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8 0
3 years ago
The length of a rectangle is 5 metres less than twice the breadth. If the perimeter is 50 meters,find the length and breadth
MAXImum [283]
<h3><u>S</u><u> </u><u>O</u><u> </u><u>L</u><u> </u><u>U</u><u> </u><u>T</u><u> </u><u>I</u><u> </u><u>O</u><u> </u><u>N</u><u> </u><u>:</u></h3>

As per the given question, it is stated that the length of a rectangle is 5 m less than twice the breadth.

Assumption : Let us assume the length as "l" and width as "b". So,

\twoheadrightarrow \quad\sf{ Length =2(Width)-5}

\twoheadrightarrow \quad\sf{ \ell=(2b-5) \; m}

Also, we are given that the perimeter of the rectangle is 50 m. Basically, we need to apply here the formula of perimeter of rectangle which will act as a linear equation here.

\\ \twoheadrightarrow \quad\sf{ Perimeter_{(Rectangle)} = 2(\ell +b) } \\

  • <em>l</em> denotes length
  • <em>b</em> denotes breadth

\\ \twoheadrightarrow \quad\sf{50= 2(2b-5+b)} \\

\\ \twoheadrightarrow \quad\sf{50= 2(3b-5)} \\

\\ \twoheadrightarrow \quad\sf{50= 6b - 10} \\

\\ \twoheadrightarrow \quad\sf{50+10= 6b} \\

\\ \twoheadrightarrow \quad\sf{60= 6b} \\

\\ \twoheadrightarrow \quad\sf{\cancel{\dfrac{60}{6}}=b} \\

\\ \twoheadrightarrow \quad\underline{\bf{10\; m = Width }} \\

Now, finding the length. According to the question,

\twoheadrightarrow \quad\sf{ \ell=(2b-5) \; m}

\twoheadrightarrow \quad\sf{ \ell=2(10)-5\; m}

\twoheadrightarrow \quad\sf{ \ell=20-5\; m}

\\ \twoheadrightarrow \quad\underline{\bf{15\; m = Length }} \\

<u>Therefore</u><u>,</u><u> </u><u>length</u><u> </u><u>and</u><u> </u><u>breadth</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>r</u><u>ectangle</u><u> </u><u>is</u><u> </u><u>1</u><u>5</u><u> </u><u>m</u><u> </u><u>and</u><u> </u><u>10</u><u> </u><u>m</u><u>.</u><u> </u>

7 0
3 years ago
Can someone help with number 18 (the scavenger hunt)? I'll give Brainliest
erik [133]
I basically converted them all into decimals and rounded
Team 1- 0.75
Team 2- 0.8
Team 3- 0.775
Team 4- 0.825
Team 5- 0.725
Team 6- 0.7625
Team 7- 0.7875
Team 8- 0.8125
Team 4 collected the most
Team 5 collected the least
6 0
3 years ago
7.92 8.055<br> 7.9<br> 7.98 8.072 8.027<br> Least to greatest
ioda

Answer:

First, we compare the given numbers using a place value chart. Since I don't have one of those, we won't be using a guide.

<u>7.92</u>

<u>8.055</u>

<u>7.9</u>

<u>7.98</u>

<u>8.072</u>

<u>8.027</u>

Comparing those, this order is the correct arrangement from least to greatest:

<u>7.9</u>

<u>7.92</u>

<u>7.98</u>

<u>8.027</u>

<u>8.055</u>

<u>8.072</u>

~Hope this helps~

8 0
3 years ago
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