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ryzh [129]
3 years ago
8

Parallelogram ABCD is reflected over the x-axis. What rule shows the input and output of the reflection, and what is the new coo

rdinate of A'?
Mathematics
1 answer:
vovangra [49]3 years ago
3 0
(x,y) ->(x,-y); A' is at (-5,-1)
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I really need help with this problem, I don't know how to do it. Please help if you can.
Stels [109]

Answer:

see below

Step-by-step explanation:

2/3 +y =1/4

Subtract 2/3 from each side

2/3-2/3 +y =1/4-2/3

y = 1/4 -2/3

Get a common denominator

y = 1/4 (3/3) - 2/3 *4/4

  = 3/12 - 8/12

  =-5/12

or if

2/(y+3) = 1/4

Using cross products

y+3 = 2*4

y+3 = 8

y =8-3

y = 5

5 0
3 years ago
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Please answer this for me!!
Fed [463]

Answer: quit

Step-by-step explanation:

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3 years ago
Can somebody answer this question? Please show work and whoever does it best get's brainliest and 5/5 stars
balandron [24]

Answer:

-49

Step-by-step explanation:

-49

5 0
3 years ago
Give an example of two numbers that are both 6-digit numbers,but the greater number is Determined by the hundreds place
VMariaS [17]

perhaps 300,900 and 300,400 ?

5 0
3 years ago
Factor by Grouping.
Komok [63]

Answer:

The ac product of 35x^2+41x+12 is <u>420</u>.

The factors of the ac product that add to 41 are <u>20</u> and <u>21</u>.

35x^2+41x+12 = (7x+4)(5x+3)

Step-by-step explanation:

1) The general form of a quadratic is ax^2 + bx + c. Hence, multiplying 35 by 12 gives you the product of ac, which is 420.

2) We need to find two numbers that multiply to 420 and add up to 41 <u>simultaneously</u>. If we pull out the factors of 420, two of them will be 20 and 21, which multiply to 420 as well as add up to 41.

3) Write 41x as a sum.

35x^2+20x+21x+12

Now, we can factor them out by grouping.

35x^2+20x+21x+12\\5x(7x+4)+3(7x+4)

Since, 7x +4 is common in both of the factors, we only take one of the 7x+4 along with 5x and 3.

(7x+4)(5x+3)

6 0
2 years ago
Read 2 more answers
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