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Gelneren [198K]
3 years ago
11

The weight distribution of parcels sent in a certain manner is normal with mean value 17 lb and standard deviation 3.3 lb. The p

arcel service wishes to establish a weight value c beyond which there will be a surcharge. What value of c is such that 99% of all parcels are at least 1 lb under the surcharge weight? (Round your answer to three decimal places.) c = lb
Mathematics
1 answer:
Yakvenalex [24]3 years ago
7 0

Answer: The value of c would be 26.514 lb.

Step-by-step explanation:

Since we have given that

Mean = 17 lb

Standard deviation = 3.3 lb

At 99%  level of significance, z = 2.58

So, it becomes,

Z=\dfrac{X-\mu}{\sigma}\\\\2.58=\dfrac{X-17}{3.3}\\\\2.58\times 3.3=X-17\\\\8.514+17=X\\\\X=25.514

So, the weight c would be

c=25.514+1\\\\c=26.514

Hence, the value of c would be 26.514 lb.

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4 0
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Find the measure of CD⎯⎯⎯⎯⎯⎯⎯⎯.<br><br> A. 8<br> B. 6<br> C. 5<br> D. 7
oee [108]

Answer:

Using the property of intersecting secant:-

(DE)(CE)=(FE)(LE)

(4)(x-1+14)=(5)(x-4+5)

4(x+3)=(5x+1)

4x+12=5x+5

4x+-5x=5-12

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So, CD=x-1=7-1=6

so,~your ~answer ~is ~B) ~6

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3 0
3 years ago
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The length of the rectangle is 5 inches more than the width. The perimeter of the rectangle is 42 inches. Write an equation to m
Sunny_sXe [5.5K]

Answer:

<h2>Length = 13 in. </h2>

 Step-by-step explanation:

perimeter of a rectangle (P) = 2L + 2W

where;

P = 42 in.  

Length (L) = 5 + W

Find:

length (L) of the rectangle

solution:

P = 2L + 2W

42 = 2(5 + W) + 2W

42 = 10 + 2W + 2W

42 - 10 = 4W

32 = 4W

W = 32/4

W = 8

Length (L) = 5 + W

                = 5 + 8

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proof:

42 = 2(13) + 2(8)

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4 0
3 years ago
Emilie rides her bike x miles before she gets a flat tire. She walks 1/3mile to a bus stop and then takes a bus for 2 1/2miles.
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Which expression shows how many miles Emilie travels in all.

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D = x + 1/3 + 5/2

D = (6x + 2 + 15)/6

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Answer:

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