Question

In the figure below, AMNO

Answer 1

Given:

$\Delta MNO\cong \Delta PQR$

To find:

The length of QR.

Solution:

We have,

$\Delta MNO\cong \Delta PQR$

Then, $MN=PQ$                 (CPCTC)

$10=4x-2$

$10+2=4x$

$12=4x$

Divide both sides by 4.

$\dfrac{12}{4}=x$

$3=x$

Similarity,

$MO=PR$            (CPCTC)

$2y+3=21$

$2y=21-3$

$2y=18$

Divide both sides by 2.

$y=9$

Now,

$x+y=3+9$

$x+y=12$

Therefore, the correct option is d.