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3 years ago

Simplify (12y^7/18y^-3) assume Y=0

Mathematics

1 answer:

iren2701 [21]3 years ago

3 0

$\dfrac{12y^7}{18y^{-3}} = \dfrac{2y^{7+3}}{3} = \dfrac{2y^{10}}{3} = \dfrac{2}{3}y^{10}$

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