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Feliz [49]
3 years ago
7

Simplify (12y^7/18y^-3) assume Y=0

Mathematics
1 answer:
iren2701 [21]3 years ago
3 0
\dfrac{12y^7}{18y^{-3}} = \dfrac{2y^{7+3}}{3} = \dfrac{2y^{10}}{3} = \dfrac{2}{3}y^{10}
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