3 years ago

How many zeros are there in -5x(x-3)(x^2-16)

1 answer:

34kurt3 years ago

4 0

Simplify:

(( - 5x)(x - 3))(x^2 - 16)

= (( -5x)(x - 3))(x^2 + - 16)

= (( -5x)(x - 3))(x^2) + (( -5x)(x - 3))( - 16)

= - 5x^4 + 15x^3 + 80^2 - 240x

= - 5x^4 + 15x^3 + 80x^2 - 240x

There are 4 Zeros...

Hope it helps!!!

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