What else would need to be congruent to show that ABC PQR by SSS?
2 answers:
Answer: C.
Step-by-step explanation:
In the given figure we have two triangles ΔABC and ΔPQR
Given:
SSS postulate of congruence says that if three sides of a triangle are congruent or equal to corresponding three sides of other triangle then the triangles must be congruent.
Therefore, we need to show that ΔABC and ΔPQR are congruent by SSS postulate of congruence.
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Answer:
No, Chancee mixed up the variables, the correct solution is that x must be between 20 and 40 and y must be between 0 and 10.
Step-by-step explanation:
Here, x and y are positive integers,
Such that, their sum is not more than 40,
i.e. x + y ≤ 40 where x, y ≥ 0,
⇒ y ≤ 40 - x ...............(1),
Their difference is at least 20,
i.e. x - y ≥ 20
-y ≥ 20 - x
⇒ y ≤ x - 20 ............(2),
Graphing y ≤ 40 - x :
Related equation of inequality (1),
y = 40 - x
if x = 0, y = 40,
if y = 0, 0 = 40 - x ⇒ x = 40,
'≤' represents a solid line,
Join the points (0, 40) and (40, 0) by solid line.
Graphing y ≤ x - 20:
Related equation of inequality (1),
y = x - 20,
if x = 0, y = -20,
if y = 0, 0 = x - 20 ⇒ x = 20,
'≤' represents a solid line,
Join the points (0, -20) and (20, 0) by solid line.
By graphing we obtained a feasible region that is the solution of the system of inequalities (1) and (2) ( shown below ),
In which,
20 ≤ x ≤ 40 and 0 ≤ y ≤ 30
Hence, Chancee did not find the correct solution.
