4 years ago

5^-4•5^4•5^0 simplified expression

Mathematics

1 answer:

7nadin3 [17]4 years ago

8 0

Answer:

The answer is in the attachment!!!

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How would you create a system of linear equations to solve using substitution for this problem?

tino4ka555 [31]

we have

x ----> number of hats the sold

y ----> number of scarves they sold

12x+15y=690 ------> equation A

y=x+10 -----> equation B

Solve the system of equations

Using substitution Method

substitute equation B in equation A

12x+15(x+10)=690

solve for x

12x+15x+150=690

27x=690-150

27x=540

x=20

Find out the value of y

y=x+10

y=20+10

y=30

therefore

The answer is

<h2>20 hats and 30 scarves</h2>

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1 year ago

There are 25 kids in a class, and the number of boys is 2/3 of the number of girls. How many boys and how many girls are in the

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15 boys
10 girls..........

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3 years ago

Please hurry i need these fast

SVETLANKA909090 [29]

Answer:

50 degrees

Step-by-step explanation:

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4 years ago

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Two corresponding sides of two similar triangles are 3cm and 5cm. The area of the first triangle is 12cm2. What is the area of t

love history [14]

Answer:

$33\dfrac{1}{3}\ cm^2$

Step-by-step explanation:

If two corresponding sides of two similar triangles are 3cm and 5cm, then the scale factor is

$k=\dfrac{a_1}{a_2}=\dfrac{3}{5}.$

Two similar triangles have their area proportional with the scale factor of $k^2.$

Hence,

$\dfrac{A_1}{A_2}=k^2,\\ \\\dfrac{12}{A_2}=\left(\dfrac{3}{5}\right)^2,\\ \\\dfrac{12}{A_2}=\dfrac{9}{25},\\ \\A_2=\dfrac{12\cdot 25}{9}=\dfrac{100}{3}=33\dfrac{1}{3}\ cm^2.$

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3 years ago

The following figure is made of six semicircles with the same diameter, and of four congruent equilateral triangles represented

Oxana [17]

6 semicircles = 3 circles

The formula of the area of a equilateral triangle:

$A_\triangle=\dfrac{a^2\sqrt3}{4}$

We have a = |AE| = 3cm. Substitute:

$A_\triangle=\dfrac{3^2\sqrt3}{4}=\dfrac{9\sqrt3}{4}\ cm^2$

The formula of the area of a circle:

$A_O=\pi r^2$

We have 2r = |AE| =3cm → r = 1.5cm. Substitute:

$A_O=\pi\cdot1.5^2=2.25\pi\ cm^2$

The area of the figure:

$A=4A_\triangle+3A_O\\\\A=4\cdot\dfrac{9\sqrt3}{4}+3\cdot2.25\pi=9\sqrt3+6.75\pi=6\dfrac{3}{4}\pi+9\sqrt3\\\\=\dfrac{27}{4}\pi+\dfrac{36\sqrt3}{4}=\dfrac{9}{4}\cdot3\pi+\dfrac{9}{4}\cdot4\sqrt3=\dfrac{9}{4}(3\pi+4\sqrt3)\ cm^2$

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3 years ago