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3 years ago

How many 2-digit positive integers are there such that the product of the product of their two digits is 24?

Mathematics

1 answer:

musickatia [10]3 years ago

5 0

I can only list four of them:. 38, 46, 64, and 83.

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Teboho has to sell a certain number of cars each month. For every car he sells over and above this number he earns 17% commissio

Nastasia [14]

The commission earned are R41123.17, R47931.67 and R15024.09

<h3>The prices of the cars before VAT was added</h3>

The VAT included prices are given as:

R271 800,00; R316 800,00 and R99 300,00.

The VAT rate is 12.36%.

So, the price before VAT is calculated as:

VAT included = Price without VAT * (1 + 12.36%)

This gives

VAT included = Price without VAT * 1.1236

So, we have:

Price without VAT = VAT included/1.1236

For the three cars, we have:

Price without VAT = R271 800.00/1.1236 = R241901

Price without VAT = R316800.00 /1.1236 = R281951

Price without VAT = R99300.00/1.1236 = R88377

Hence, the prices of the cars before VAT was added are R241901, R281951 and R88377

<h3>The commission he earned on the cars.</h3>

This is calculated as:

Commission = Price * 17%

So, we have:

Commission = R241901 * 17% = R41123.17

Commission = R281951 * 17% = R47931.67

Commission = R88377 * 17% = R15024.09

Hence, the commission earned are R41123.17, R47931.67 and R15024.09

Read more commission at:

brainly.com/question/20987196

#SPJ1

3 0

1 year ago

Given that

timofeeve [1]

Answer:

Step-by-step explanation:

(sec α - tan α)(sec α + tan α) = sec^2 α - tan^2α

But sec^2 α = 1 + tan^2 α so

sec^2 α - tan^2α = 1 + tan^2 α - tan^2α

= 1

so 1 = (sec α - tan α)(sec α + tan α) = 1/4 * x where x is sec α + tan α

1/4 * x = 1

x = 4.

6 0

3 years ago

The value of a car is $ 16,000 and depreciating at a rate of 11% per year. Write an

Mandarinka [93]

Answer- 16,000(0.88)t.

6 0

3 years ago

What is 5c2×(3/4)2×(1/4)5-2

Jobisdone [24]

Very hard question....

7 0

3 years ago

Get the general term for the sequence being your t3 = 11 and the t20 = 244.2

marusya05 [52]

Answer:

nth term = $t_{n} = 7.639(1.2)^{n - 1}$

Step-by-step explanation:

Let us assume that the given sequence is a G.P.

Now, if the first term of the G.P. is a and the common ratio is r, then

Third term = $t_{3} = ar^{2} = 11$ .......... (1) and

20th term = $t_{20} = ar^{19} = 244.2$ ........... (2)

Now, dividing equation (2) with equation (1) we get

$\frac{ar^{19} }{ar^{2} } = \frac{244.2}{11} = 22.2$

⇒ $r^{17} = 22.2$

⇒ r = 1.2.

Hence, from equation (1) we get

a(1.2)² = 11

⇒ a = 7.639 (Approx.)

Therefore, the general term of the sequence i.e. nth term = $t_{n} = 7.639(1.2)^{n - 1}$ (Answer)

5 0

3 years ago