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Lelechka [254]
3 years ago
15

1.2, 3, 7.5, 18.75, ... Which formula can be used to describe the sequence?

Mathematics
2 answers:
Nady [450]3 years ago
5 0

Answer:

The formula is:

a_n=1.2(\frac{5}{2})^{n-1}

Step-by-step explanation:

The geometric sequences are those in which the division between the terms a_{n + 1} and a_n of the sequence are equal to a constant common reason called "r"

The geometrics secencias have the following form:

a_n=a_1(r)^{n-1}

Where a_1 is the first term of the sequence

In this sequence we have the following terms

1.2, 3, 7.5, 18.75

Then notice that:

\frac{3}{1.2}=\frac{5}{2}\\\\\frac{7.5}{3}=\frac{5}{2}\\\\\frac{18.75}{7.5}=\frac{5}{2}

Then:

r=\frac{5}{2}  and a_1=1.2

Finally the formula is:

a_n=1.2(\frac{5}{2})^{n-1}

Klio2033 [76]3 years ago
5 0

Answer:

Answer: "f(x) = 1.2(2.5)x-1"

Step-by-step explanation:

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A truck travels beneath an airplane that is moving 160 km/h at an angle of 54.0 ◦ to the ground. How fast must the truck travel
Maksim231197 [3]

Answer:

2. 94.0 km/h

Step-by-step explanation:

since the airplane is moving at angle of 54° from the ground, the horizontal component of the velocity is given by cos component

speed of air plane= 160 km/hr

horizontal component of velocity v= 160 cos 54°

= 94.045 km/hr

Thus  the truck must travel at an speed of  94.0 Km/hr hence second option is correct.

6 0
3 years ago
The accompanying data came from a study of collusion in bidding within the construction industry. No. Bidders No. Contracts 2 6
viktelen [127]

Answer:

a)

The proportion of contracts involved at most five bidders is 0.667.

The proportion of contracts involved at least five bidders is 0.51.

b)

The  proportion of contracts involved  between five and 10 inclusive bidders is 0.5.

The  proportion of contracts involved  strictly between five and 10 bidders is 0.304.

Step-by-step explanation:

No. bidders    No. contracts     Relative frequency of contracts

2                         6                       6/102=0.0588

3                         20                     20/102=0.1961

4                         24                     24/102=0.2353

5                         18                       18/102=0.1765

6                         13                        13/102=0.1275

7                          7                          7/102=0.0686

8                          5                          5/102=0.049

9                          6                          6/102=0.0588

10                         2                           2/102=0.0196

11                          1                            1/102=0.0098

Total                  102

a)

We have to find proportion of contracts involved at most five bidders.

Proportion of at most 5= Relative frequency 2+ Relative frequency 3+ Relative frequency 4+ Relative frequency 5

Proportion of at most 5=0.0588+ 0.1961+0.2353+0.1765

Proportion of at most 5=0.6667

The proportion of contracts involved at most five bidders is 0.667.

proportion of at least five bidders= proportion≥5= 1- proportion less than 5

Proportion less than 5=0.0588+ 0.1961+0.2353=0.4902

proportion of at least five bidders=1-0.4902=0.5098

The proportion of contracts involved at least five bidders is 0.51

b)

We have to find proportion of contracts involved  between five and 10 inclusive bidders.

Proportion of contracts between five and 10 inclusive= Relative frequency 5+ Relative frequency 6+ Relative frequency 7+ Relative frequency 8+ Relative frequency 9+ Relative frequency 10

Proportion of between five and 10 inclusive=0.1765 +0.1275 +0.0686 +0.049 +0.0588 +0.0196

Proportion of between five and 10 inclusive=0.5

The  proportion of contracts involved  between five and 10 inclusive bidders is 0.5

We have to find proportion of contracts involved  strictly between five and 10 bidders.

Proportion of contracts strictly between five and 10=  Relative frequency 6+ Relative frequency 7+ Relative frequency 8+ Relative frequency 9

Proportion of strictly between five and 10=0.1275 +0.0686 +0.049 +0.0588

Proportion of strictly between five and 10=0.3039

The  proportion of contracts involved  strictly between five and 10 bidders is 0.304.

8 0
3 years ago
$20.600 at 8% for 2 years
balu736 [363]

Answer:

$3.296

Step-by-step explanation:

Simple interest=PRT/100

P=Principal=$20.600

R=rate=8%

T=time=2yrs

=20.600×8/100×2

=$3.296

6 0
3 years ago
A teacher wrote this experssion on the board (-6)(2)+(-8÷4) what is the vaule of this expression
VLD [36.1K]

Answer:

-14

Step-by-step explanation:

(-12)+(-2)

You solve using Pemdas, doing the (-8/4) first, and then doing (-6)(2)

The answer is the two values added together.

3 0
2 years ago
Perry finished a 100-meter race in 7/8 of a minute. The winner of the race used 14/15 of Perry's time to finish the race. How mu
konstantin123 [22]

Answer:

49 seconds

Step-by-step explanation:

The time perry used is 7/8 of a minute

a minute equals to 60 seconds

so the time perry used is 7/8 x 60 = 52.5 seconds

The winner used 14/15 of 52.5 seconds (perrys time)

so 14/15 x 52.5 = 49 seconds

3 0
3 years ago
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