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nikitadnepr [17]
2 years ago
8

We conduct a study to determine whether the majority of community college students plan to vote in the next presidential electio

n. We choose a significance level of 0.05. We survey 650 randomly selected community college students and find that 54% of them plan to vote. The P-value is 0.02. H0: 50% of community college students plan to vote in the next presidential election. Ha: More than 50% of community college students plan to vote in the next presidential election. What can we conclude
Mathematics
1 answer:
Marizza181 [45]2 years ago
4 0

Answer:

we can conclude that more than 50% of community college students plan to vote in the next presidential election

Step-by-step explanation:

Decision Rule

If;

P-value > significance level --- accept Null hypothesis

P-value < significance level --- reject Null hypothesis

Z score > Z(at 95% confidence interval) ---- reject Null hypothesis

Z score < Z(at 95% confidence interval) ------ accept Null hypothesis

Null hypothesis H0: 50% of community college students plan to vote in the next presidential election

H0: p = 0.50

Ha: More than 50% of community college students plan to vote in the next presidential election

Ha: p > 0.50

P-value = 0.02

From the decision rule;

Since the p-value for this study is less than the significance level.

0.02 < 0.05

So, we reject the null hypothesis, there is enough evidence to reject the null hypothesis. We thereby accept the alternative hypothesis.

Therefore, we can conclude that more than 50% of community college students plan to vote in the next presidential election

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Help with this question, please!
Katyanochek1 [597]

The diet will include <u>123.75 </u>daily grams of protein

<h3>Further explanation</h3>

One variable linear equation is an equation that has a variable and the exponent number is one.  

Can be stated in the form:  

\large{\boxed{\bold{ax=b}}

or  

ax + b = c, where a, b, and c are constants, x is a variable  

We complete the task :

A nutritionist planning a diet for a football player wants him to consume 3,500 Calories and 725 grams of food daily. Calories from fat and protein will be 45% of the total Calories. There are 4, 4, and 9 Calories per gram for protein, carbohydrates, and fat, respectively. How many daily grams of protein will the diet include?

  • 243.75
  • 481.25
  • 123.75
  • 120

Calories from fat and protein will be 45% (0.45) of the total Calories

Calories from fat and protein = 0.45 x 3500 = 1575 calories

Calories from carbohydrates = 3500 - 1575 = 1925 calories

So mass for carbohydrates = 1925 : 4(4 calories/gram) = 481.25 grams

Then mass for fat and protein = 725 - 481.25 = 243.75 grams

We can make equation for fat and protein

1. 4 calories. mass of protein(p) + 9 calories . mass of fat(f) = 1575 calories

2. mass of protein(p) + mass of fat(f) = 243.75

we can simplify :

1. 4p+9f = 1575

2. p + f = 243.75 ⇒ f = 243.75 - p

we substitute equation 2 into equation 1 :

4p + 9(243.75-p) = 1575

4p + 2193.75-9p=1575

-5p = -618.75

p = 123.75

<h3>Learn more</h3>

linear equation

brainly.com/question/99841

Keywords : one variable, linear equation ,diet, nutritionist,calories, fat, proteins, carbohydrates, daily grams

#LearnWithBrainly

6 0
3 years ago
Please answer correctly !!!!!!!!! Will mark brainliest !!!!!!!!!!!!!!!
Ugo [173]

Answer:

Step 3  they took the square root incorrectly

Step-by-step explanation:

5 ( x-2)^2 +6 = 86

Subtract 6 from each side

5 ( x-2)^2 +6 -6= 86-6

5 ( x-2)^2  = 80

Divide each side by 5

5 ( x-2)^2  /5 = 80/5

(x-2)^2 = 16

Take the square root of each side

sqrt((x-2)^2)  = ±sqrt(16)

x-2 = ±4

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All you have to do is plug in.

x = 1 , y= 8

3x+5=y

3(1) + 5 = 8

3+5 = 8

8=8

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3 years ago
A 28-year-old man pays $181 for a one-year life insurance policy with coverage of $150,000. If the probability that he will live
Marina CMI [18]
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What is an equation in pointelope form for the line that passes through the points (4. – 1) and (-3,0)
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1/3

Step-by-step explanation:

2nd one

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