Which quadrant would contain the point -3, 3please help!thankyou!
2 answers:
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Considering the linear functions on the graph, the inequality that matches the situation is:
B.
A linear function is modeled by:
y = mx + b
In which:
- m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.
- b is the y-intercept, which is the value of y when x = 0, and can also be interpreted as the initial value of the function.
The lower bound of the interval is a linear function with y-intercept of b = 2, that also passes through (2,3), hence the slope is:
m = (3 - 2)/(2 - 0) = 1/2.
Hence the inequality is:
The upper bound of the interval is a linear function with y-intercept of b = 1, that also passes through (2,5), hence the slope is:
m = (5 - 1)/(2 - 0) = 2.
Hence the inequality is:
More can be learned about linear functions at brainly.com/question/24808124
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Answer:
11 and -11
Step-by-step explanation:
This problem can really only be solved either by way of a calculator or simple memorization. In this case, the product (121) is a perfect square root, meaning it has a whole number answer. One square root of 121 is 11. The second square root of 121 is -11.
You can check your work by squaring your answer and seeing whether it equals the product. Remember, a negative number times another negative number results in a positive answer.