Simplify the expression: 4(2a)+7(-4b)+(3b-5)

Mathematics

1 answer:

Alexus [3.1K]3 years ago

8 0

8a-25b-5 is the answer to ur question

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Here to you!!!!!!!! now prove it

Andrew [12]

Answer:

teenagers who watch TV =2

teenagers wearing glasses =5

hence probability =2/5=0.4

now you prove how ur answer is 0.5

7 0

3 years ago

What is the probability of randomly selecting a month pf year and not getting a month that ends in y?

Umnica [9.8K]

Answer:

2/3

Step-by-step explanation:

The months whose names end in 'y' include Jan, Feb, May, Jul. The probability of randomly selecting a month whose name ends in 'y' is 4/12 (remember that there are 12 months in a year), or 1/3.

Thus, the probability of selecting a month whose name does NOT end in 'y' is 8/12, or 2/3. Note that this event is the 'complement' of the first event:

P(name does not end in 'y') = 1 - P(name does not end in 'y') = 1 - 1/3 = 2/3

8 0

2 years ago

Find a number C such that the polynomial p(x)= -x+4x^2+Cx^3-8x^4

Ksenya-84 [330]

Answer:

C = 2

Step-by-step explanation:

$p(x)= -x+4x^2+Cx^3-8x^4 \\ \\ \because \: given \: polynmial \: has \: zero \: at \: \\x = \frac{1}{4} \\ \\ \implies \: p\bigg(\frac{1}{4} \bigg) = 0...(1) \\ \\ plug \: x = \frac{1}{4} \: in \: p(x) \: we \: find \\ \\ p \bigg(\frac{1}{4} \bigg) = - \frac{1}{4} + 4 {\bigg(\frac{1}{4} \bigg)}^{2} + c {\bigg(\frac{1}{4} \bigg)}^{3} - 8 {\bigg(\frac{1}{4} \bigg)}^{4} \\ \\ 0 = - \frac{1}{4} + \cancel 4 \times {\frac{1}{\cancel{16} } } + c {\bigg(\frac{1}{64} \bigg)} - \cancel 8 \times \frac{1}{\cancel{256} } \\ \\0 =\cancel{ - \frac{1}{4}} + \cancel {{\frac{1}{4} }} + c {\bigg(\frac{1}{64} \bigg)} - \times \frac{1}{32} \\ \\0 = c {\bigg(\frac{1}{64} \bigg)} - \frac{1}{32} \\ \\c {\bigg(\frac{1}{64} \bigg)} = \frac{1}{32} \\ \\ c = \frac{1}{32} \times 64 \\ \\ c = 2$