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Juli2301 [7.4K]

3 years ago

15

Simplify the expression: 4(2a)+7(-4b)+(3b-5)

1 answer:

Alexus [3.1K]3 years ago

8 0

8a-25b-5 is the answer to ur question

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Use the Order of Operations to simplify: 3(8 - 4*5)

aleksklad [387]

Answer:

<h2>-36</h2>

Step-by-step explanation:

$3\left(8-4\cdot \:5\right)\\\mathrm{Follow\:the\:PEMDAS\:order\:of\:operations}\\\\\mathrm{Calculate\:within\:parentheses}\:\left(8-4\cdot \:5\right)\::\quad -12\\=3\left(-12\right)\\\\\mathrm{Multiply\:and\:divide\:\left(left\:to\:right\right)}\:3\left(-12\right)\:\\:\quad -36$

3 0

2 years ago

Read 2 more answers

Which of the following expressions represents the LCM of 91x2y and 104xy3?

GaryK [48]

The answer is {B} 728x2y3.

5 0

3 years ago

The expression 21 - (2x + 3)2 + 4 (1 - 1) + z3 can be simplified into the form

mr Goodwill [35]

Answer:

A=z

B=-2

C=0

D=30

Step-by-step explanation:

First lets simply the equation

21 - (2x +3)2 + 4(1-1) + z^3

21 - (2x^2 + 9) + 4(0) + z ^3

21 - 2x^2 + 9 + z^3

- 2x^2 + z ^3 + 30

This means that:

A=z

B=-2

C=0

D=30

5 0

3 years ago

Angle e measures 126LaTeX: ^\circ∘. What is the measure of LaTeX: \angle∠h?

Oksana_A [137]

Option C: 126° is the correct answer

Step-by-step explanation:

When two lines intersect, the four angles are formed. The angles vertically opposite with same vertex are called vertical opposite angles.

The opposite vertical angles are equal.

In the given figure, the pairs of vertically opposite angles are e,h and f,g.

Given

∠e = 126°

The measurement of e and h will be equal as they are vertically opposite

So,

m∠e = m∠h

m∠h = 126°

Hence,

Option C: 126° is the correct answer

Keywords: Vertical angles, lines

Learn more about angles at:

#LearnwithBrainly

6 0

2 years ago

A certain semiconductor device requires a tunneling probability of T = 10-5 for an electron tunneling through a rectangular barr

Goryan [66]

Answer:

Generally the barrier width is $a = 1.9322 *10^{-9} \ m$

Step-by-step explanation:

From the question we are told that

The tunneling probability required is $T = 1 * 10^{-5}$

The barrier height is $V_o = 0.4 eV$

The electron energy is $E = 0.08eV$

Generally the wave number is mathematically represented as

$k = \sqrt{ \frac{2 * m [V_o - E]}{\= h^2} }$

Here m is the mass of the electron with the value $m = 9.11 *10^{-31} \ kg$

h is is know as h-bar and the value is $\= h = 1.054*10^{-34} \ J \cdot s$

So

$k = \sqrt{ \frac{2 * 9.11 *10^{-31 } [0.4 - 0.04] * 1.6*10^{-19}}{[1.054*10^{-34}^2]} }$

=> $k = 3.073582 *10^{9} \ m^{-1}$

Generally the tunneling probability is mathematically represented as

$T = 16 * \frac{E}{V_o } * [1 - \frac{E}{V_o} ] * e^{-2 * k * a}$

So

$1.0 *10^{-5} = 16 * \frac{0.04}{0.4 } * [1 - \frac{0.04}{0.4} ] * e^{-2 * 3.0736 *10^{9} * a}$

=> $6.944*10^{-6}= e^{-2 * 3.0736 *10^{9} * a}$

Taking natural log of both sides

$ln[6.944*10^{-6}] = -2 * 3.0736 *10^{9} * a}$

=> $-11.8776 = -2 * 3.0736 *10^{9} * a}$

=> $a = 1.9322 *10^{-9} \ m$

4 0

2 years ago