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VladimirAG [237]
3 years ago
13

Tyson can type 49 words per minute. How long will it take him to type a 1000-word essay?

Mathematics
1 answer:
earnstyle [38]3 years ago
8 0

Answer:

<u>20.4minutes</u>

Step-by-step explanation:

<em>Duration= Number of words/Typing speed</em>

<em>Duration</em><em>=</em><em> </em><em>100</em><em>0</em><em>/</em><em> </em><em>49</em><em> </em><em>per</em><em> </em><em>min</em>

<em>=</em><em> </em><em>20.4minutes</em><em> </em>

Hope this helped you- have a good day bro cya)

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liraira [26]

Answer:

150 i think

Step-by-step explanation:

4 0
3 years ago
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Use algebraic rules of equations to predict the solution to the system of equations. Include all of your work for full credit.
bezimeni [28]
Use substitution
x+(2x-1)=-4
3x-1=-4
3x=-3
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7 0
4 years ago
Solve for n, please i would really appreciate it :)
Lelu [443]

Answer:

2

Step-by-step explanation:

{ {a}^{b} }^{c}  =  {a}^{bc } \\ in \: this \: case \\  { ({8}^{n}) }^{3}  =  {8}^{3n}  \\ \\  {8}^{3n}  =  {8}^{6 }  \\ 3n = 6 \\ n =  \frac{6}{3}  = 2

6 0
3 years ago
Complete the equation of the line through (-9,-9)(−9,−9)left parenthesis, minus, 9, comma, minus, 9, right parenthesis and (-6,0
saw5 [17]

Answer:

The equation of the line is;

y = 3x + 18

Step-by-step explanation:

We want to write the equation of the line through (-9,-9) and (-6,0)

we start by calculating the slope of the line

m = (y2-y1)/(x2-x1) = (0+ 9)/(-6+9) = 9/3 = 3

The general equation of the line is;

y = mx + c

y = 3x + c

To get c, we use any of the points

we substitute for example -6 for x and 0 for y

0 = 3(-6) + c

c = 0 + 18 = 18

So the equation of the line is;

y = 3x + 18

4 0
3 years ago
Sherman has two sequences . The first sequence is described by the explicit rule f(n) = 15n + 4 and the second sequence is descr
Viktor [21]

Answer:

Step-by-step explanation:

Given the explicit function as

f(n) = 15n+4

The first term of the sequence is at when n= 1

f(1) = 15(1)+4

f(1) = 19

a = 19

Common difference d = f(2)-f(1)

f(2) = 15(2)+4

f(2) = 34

d = 34-19

d = 15

Sum of nth term of an AP = n/2{2a+(n-1)d}

S20 = 20/2{2(19)+(20-1)15)

S20 = 10(38+19(15))

S20 = 10(38+285)

S20 = 10(323)

S20 = 3230.

Sum of the 20th term is 3230

For the explicit function

f(n) = 4n+15

f(1) = 4(1)+15

f(1) = 19

a = 19

Common difference d = f(2)-f(1)

f(2) = 4(2)+15

f(2) = 23

d = 23-19

d = 4

Sum of nth term of an AP = n/2{2a+(n-1)d}

S20 = 20/2{2(19)+(20-1)4)

S20 = 10(38+19(4))

S20 = 10(38+76)

S20 = 10(114)

S20 = 1140

Sum of the 20th terms is 1140

7 0
3 years ago
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