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3 years ago

(2.5×10^−10)(7×10^−6)

1 answer:

6 0

<span>(2.5×10^−10)(7×10^−6)
= (2.5 x 7) (</span>10^−10 x 10^−6)
= 17.5 x 10^-16
= 1.75 x 10^-15

answer
<span>B. 1.75×10^−15 </span>

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The number of real zeros of the function f(x) = x3 + 4x2 + x − 6 is 3

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The equation of the function is given as:

$f(x) = x^3 + 4x^2 + x - 6$

Expand the function

$f(x) = x^3 + 5x^2 - x^2 + 6x - 5x - 6$

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$f(x) = x^3 + 5x^2 + 6x - x^2 - 5x - 6$

Factor the expression

$f(x) = x(x^2 + 5x + 6) -1(x^2 + 5x + 6)$

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Expand

$f(x) = (x^2 + 3x + 2x + 6)(x -1)$

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Factor out x + 2

$f(x) = (x + 3)(x + 2)(x- 1)$

The function has been completely factored and it has 3 linear factors

Hence, the number of real zeros of the function f(x) = x3 + 4x2 + x − 6 is 3