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Nataly_w [17]
3 years ago
5

If a gold bar has a length of 17.78 cm, a width of 9.208 cm, a height of 4.445 cm, and the density of gold is 19.3 g/cm^3, what

is the
mass of the gold bar. Answer with the correct number of significant figures. Use the rounding rules.

A. 1.40x10^4 grams
B. 14 040 grams
C. 14 045.142 grams
D. 14 045 grams
Mathematics
1 answer:
kozerog [31]3 years ago
4 0

Answer:

17.78×9.208×4.445=727.7275768

D=mass÷volume

mass=density×volume

mass=19.3g/cm3×727,7275768=14045,14223224=14045grams

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Answer:

A) 12x + 10y

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Step-by-step explanation:

A) A fórmula para calcular o perímetro de um retângulo é dada como:

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A) A pergunta nos diz que:

O comprimento de um retângulo é 6x e sua largura é 5y.

A expressão algébrica que representa o perímetro do retângulo =

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L = 6x, W = 5y

= 2 (6x) + 2 (5y)

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A expressão algébrica que representa o perímetro do retângulo é

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y = 7cm

Perímetro = 12 (4) + 10 (7)

Perímetro = 48cm + 70cm

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Step-by-step explanation:

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