Answer: 6 wagons will be needed
Step-by-step explanation:
36/6=6
The ratio of red to green is 5:6 which means that for every 5 red cars, there are 6 green cars
The ratio of green to blue is 3:10 telling us that for every 3 green cars, there are 10 blue cars.
The ratio 3:10 is equivalent to 6:20 after we multiply both parts by 2. This now says that for every 6 green cars, there are 20 blue cars.
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Let's say we had 5 red cars, 6 green cars and 20 blue cars
Based on that info, we know that the ratio of red to green is 5:6
And the ratio of green to blue is 6:20 which reduces to 3:10
We don't reduce 6:20 to 3:10 however, since that would change the green count from 6 to 3. We want to keep the green count at 6.
So because there are 5 red cars, 6 green cars, and 20 blue cars in this example, and this example points to the proper ratios mentioned earlier, this means that the final answer is 5:6:20. This ratio cannot be reduced or simplified as there are no common factors (other than 1) for 5, 6, and 20.
Answer:
4480n^3
Step-by-step explanation:
just multiply 80n x 56n and get 4480n but since 80n is to the 2nd and 56n is to the first add them to get to the power of 3 and put that on 4480n
Answer:
True, false, true, true.
Step-by-step explanation:
The roots zeros of a quadratic function are the same as the factors of the quadratic function. This is true because your roots are your factors—>(x-3) is a factor, x=3 is the root.
The roots zeros are the spots where the quadratic function intersects with the y-axis. No! Those are called y-intercepts!
The roots zeros are the spots where the quadratic function intersects with the x-axis. True. X-intercepts are your solutions. (x-3) graphed would the (3,0). That’s a solution.
There are not always two roots/zeros of a quadratic function, True. No solution would be when your quadratic doesn’t intersect the x-axis. One solution would be when your vertex would be on the x-axis. Two solutions is when your quadratic intersects the x-axis twice. Can there be infinite solutions? No. It’s either 0, 1, or 2 solutions.
