All categories

2 years ago

Please help me I’m stuck!!!

Mathematics

1 answer:

Klio2033 [76]2 years ago

5 0

Answer:

The point (0, 6.7) is the point where the ball was launched.

Step-by-step explanation:

The ball was launched from a point 6.7 feet from ground level.

In this scenario (ball tossed toward the goal), the constant c at the end of the function formula gives you the initial position (height).

You might be interested in

Alison wants to find out how much time people spend reading books. She is going to use a questionnaire.

neonofarm [45]

Well, for her questionnaire she could use and create questions or queries that are obviously related to her hypothesis or study. These could be done in a likert type of scale. 
1. I read most often.
 a. Strongly Agree b. Agree c. Disagree d. Strongly Disagree 

2. When I read my books its takes me 24 hours a day 
a. Strongly Agree b. Agree c. Disagree d. Strongly Disagree 

3. When I start reading I can’t stop 
a. Strongly Agree b. Agree c. Disagree d. Strongly Disagree

5 0

2 years ago

Lines k and n intersect on the y-axis

avanturin [10]

a) The equation of line k is:

$y = -\frac{202}{167}x + \frac{598}{167}$

b) The equation of line j is:

$y = \frac{167}{202}x + \frac{1546}{202}$

The equation of a line, in slope-intercept formula, is given by:

$y = mx + b$

In which:

m is the slope, which is the rate of change.
b is the y-intercept, which is the value of y when x = 0.

Item a:

Line k intersects line m with an angle of 109º, thus:

$\tan{109^{\circ}} = \frac{m_2 - m_1}{1 + m_1m_2}$

In which $m_1$ and $m_2$ are the slopes of k and m.

Line k goes through points (-3,-1) and (5,2), thus, it's slope is:

$m_1 = \frac{2 - (-1)}{5 - (-3)} = \frac{3}{8}$

The tangent of 109 degrees is $\tan{109^{\circ}} = -\frac{29}{10}$
Thus, the slope of line m is found solving the following equation:

$\tan{109^{\circ}} = \frac{m_2 - m_1}{1 + m_1m_2}$

$-\frac{29}{10} = \frac{m_2 - \frac{3}{8}}{1 + \frac{3}{8}m_2}$

$m_2 - \frac{3}{8} = -\frac{29}{10} - \frac{87}{80}m_2$

$m_2 + \frac{87}{80}m_2 = -\frac{29}{10} + \frac{3}{8}$

$\frac{167m_2}{80} = \frac{-202}{80}$

$m_2 = -\frac{202}{167}$

Thus:

$y = -\frac{202}{167}x + b$

It goes through point (-2,6), that is, when $x = -2, y = 6$ , and this is used to find b.

$y = -\frac{202}{167}x + b$

$6 = -\frac{202}{167}(-2) + b$

$b = 6 - \frac{404}{167}$

$b = \frac{6(167)-404}{167}$

$b = \frac{598}{167}$

Thus. the equation of line k, in slope-intercept formula, is:

$y = -\frac{202}{167}x + \frac{598}{167}$

Item b:

Lines j and k intersect at an angle of 90º, thus they are perpendicular, which means that the multiplication of their slopes is -1.

Thus, the slope of line j is:

$-\frac{202}{167}m = -1$

$m = \frac{167}{202}$

Then

$y = \frac{167}{202}x + b$

Also goes through point (-2,6), thus:

$6 = \frac{167}{202}(-2) + b$

$b = \frac{(2)167 + 202(6)}{202}$

$b = \frac{1546}{202}$

The equation of line j is:

$y = \frac{167}{202}x + \frac{1546}{202}$

A similar problem is given at brainly.com/question/16302622

7 0

2 years ago

For every 6kg a child's weight, pediatricians prescribe 17mg of acetaminophen. If Lexie weighs 48 kg, how many milligrams of the

Inessa05 [86]

The answer will be 136mg
48/6=8
8*17=136mg

3 0

2 years ago

Please help i need to finish

elena-s [515]

Answer:

B. $\overline A \overline C \cong \overline B \overline D$

Step-by-step explanation:

The hypotenuse leg theorem (HL) requires the proof that the hypotenuse and the corresponding leg of the triangles to be equal in length. From the diagram, it can be found that $\overline D \overline C$ is a common (shared) side of both triangles, so the additional fact needed is for the hypotenuses to be the same length.

∴ $\overline A \overline C \cong \overline B \overline D$ is the additional fact needed to prove $\triangle ADC \cong \triangle BCD$

Hope this helps :)

5 0

2 years ago

Shoutout to my sister amckeon88

kotykmax [81]

Periodt Pooh. For brainly??

4 0

2 years ago