To find the product of (4x-5y)^2,
we can rewrite the problem as:
(4x-5y)(4x-5y) (two times because it is squared)
Now, time to use that old method we learned in middle school:
FOIL. (Firsts, Outers, Inners, and Lasts)
FOIL can help us greatly in this scenario.
Let's start by multiplying the 'Firsts' together:
4x * 4x = <em>16x^2</em>
Now, lets to the 'Outers':
4x * -5y = <em>-20xy</em>
Next, we can multiply the 'Inners':
-5y * 4x = <em>-20xy</em>
Finally, let's do the 'Lasts':
-5y * -5y = <em>25y</em>^2
Now, we can take the products of these equations from FOIL and combine like terms. We have: 16x^2, -20xy, -20xy, and 25y^2.
-20xy and -20xy make -40xy.
The final equation (product of (4x-5y)^2) is:
16x^2 - 40xy + 25y^2
Hope I helped! If any of my math is wrong, please report and let me know!
Have a good one.
Answer:
xy=8
Step-by-step explanation:
The equation for inverse variation is
xy = k where k is the constant of variation
4*2 = k
8=k
The equation is
xy=8
Answer:
5 10/12
Step-by-step explanation:
using BODMAS
1/2×2/3=1/3
THEN; 5 1/4+1/3
Change 5 1/4 to 21/4 then add to 1/3
you get 70/12
divide 70÷12
answer 5 10/12
hope it helped
Answer: 9
Step-by-step explanation:
4+6x+5=7x
-6x -6x
=
4+5=1x
9=1x
X=9
