What is (-i)^6? I need help please....

Mathematics

2 answers:

mel-nik [20]3 years ago

6 0

Answer: -1

Step-by-step explanation:

beks73 [17]3 years ago

5 0

Answer:

Step-by-step explanation:

-i= -i

-i^2= 1

-i^3= -i * 1 = -i

-i^4= 1 * (-1) = -1

-i^5= -i

-i^6= 1

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Describe the solutions for the quadratic equation shown below:

PtichkaEL [24]

The solutions for the quadratic equation 9x² - 6x + 5 = 0 are A. 2 complex roots

To determine the the type of roots the quadratic equation 9x² - 6x + 5 = 0, we use the quadratic formula to find the roots.

So, for a quadratic equation ax + bx + c = 0, the roots are

$x = \frac{-b +/- \sqrt{b^{2} - 4ac} }{2a}$

With a = 9, b = -6 and c = 5, the roots of our equation are

$x = \frac{-(-6) +/- \sqrt{(-6)^{2} - 4 X 9 X 5} }{2 X 9} \\x = \frac{6 +/- \sqrt{36 - 180} }{18} \\x = \frac{6 +/- \sqrt{-144} }{18} \\x = \frac{6 +/- \sqrt{-12} }{18}\\x = \frac{6}{18} +/- i\frac{12}{18} \\x = \frac{1}{3} +/- i\frac{2}{3} \\x = \frac{1 + 2i}{3} or \frac{1 - 2i}{3}$