Infinite intervals are closed if they contain a finite endpoint, and open otherwise. The entire real line is an infinite interval that is both open and closed
It’s 65.41 rounded to the nearest hundredth
A(0,-1)
B(3√3/3, 2)
Slope of AB = (y₂ - y₁)/(x₂-x₁)
Slope = (2-1)/(√3/3 , -0)
Slope = 1/√3/3 = 1/√3 = √3/3
OR SLOPE = tan(a°) = √3/3 and a° = 30°
"r < 3 or r > 2" is the one among the following choices given in the question that <span>could have resulted in this solution set. The correct option among all the options that are given in the question is the fourth option or option "d". I hope that this is the answer that has actually come to your desired help.</span>
Answer:
(5r-4)(4r^(2)+3)
Step-by-step explanation:
Hope it helps
