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Nataly [62]
4 years ago
13

I'LL GIVE BRAINLIEST !!! FASTERR !​

Mathematics
1 answer:
Talja [164]4 years ago
3 0

Answer:

opt. B

Step-by-step explanation:

g=60 because equilateral triangle ang=60

<KMN=120 because of linear pair

<h= 180-(120+29)= 31

g+h= 60+31= 91

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Change -1.75 to degree measure &amp; round to the nearest tenth
Dima020 [189]

Answer:

I believe the answer is D-100.3 degrees, however, I'm not 100% sure.

Step-by-step explanation:


3 0
3 years ago
3a <br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B3a%20%2B%20a%20%7B%7D%5E%7B2%7D%20%7D%7Ba%7D%20" id="TexFormula1" title="
egoroff_w [7]

Answer:

(3+a)

Step-by-step explanation:

3a + a^2

-------------

a

Factor out an a in the numerator

a(3+a)

-------------

a

Cancel like terms

(3+a)

6 0
3 years ago
Read 2 more answers
A shopkeeper marked the price of an article a certain percent above the cost price and he allowed 16% discount to make 5% profit
zhuklara [117]

Answer:

25%

Step-by-step explanation:

let the MP be x

sp without vat =x-16%of x

= 21x/25

sp with VAT = 21x/25 +13% of 21x/25

rs 9492 = 2373x/2500

( 9492*2500)/2373=x

x = 10000

cp = ((21x/25 )*100)/100+5 ( 5= profit percent )

=8000

(10000-8000)×100%/8000

=25%

7 0
3 years ago
If P'(-1,-3) is obtained by a 180ºccw rotation about the origin what are the coordinates of P?
Nuetrik [128]
-1,3 because your moving the quadrant counter clockwise into the 2nd quadrant
4 0
4 years ago
Elijah and his sister went to the movies. They had 34 altogether and spent 9.50 per ticket. Elijah and his sister bought the sam
Zarrin [17]

Answer:

The Inequality to find the amount of money they spent on snack is 2(9.5+x)\leq 34

Maximum amount each person can spent on snack is 7.5.

Step-by-step explanation:

Given:

Total Money they had = 34

Cost of each ticket = 9.5

Number of persons = 2

Let the cost of snacks bought by each be x.

We need to write inequality and solve for the amount each persons spent on snacks.

Solution:

Now we can say that;

Number of persons multiplied by sum of Cost of each ticket and Cost of each person spent on snack should be less than or equal to Total money they had.

framing in equation form we get;

2(9.5+x)\leq 34

Hence the Inequality to find the amount of money they spent on snack is 2(9.5+x)\leq 34

On Solving the above Inequality we get;

2(9.5+x)\leq 34\\\\19+2x\leq 34

Now By Using Subtracting property of Inequality we will subtract both side by 19 we get;

19+2x-19\leq 34-19\\\\2x\leq 15

No By Division Property of Inequality we will divide both side by 2 we get;

\frac{2x}{2}\leq \frac{15}{2}\\\\x\leq 7.5

Hence maximum amount each person can spent on snack is 7.5.

Interpreting the solution we get;

Now Cost of 1 ticket = $9.5

Number of person = 2

So total cost of ticket = $19

Total money they have = $34

Money left = Total money - total cost of ticket =$34 -$19 = $15

Amount of money left = $15

Now each buys the same snack.

So maximum amount of money each can spent on snack = $7.5

5 0
3 years ago
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