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3 years ago

6

Lee earned some money from a summer job he saved 1/4 of the money and spent 1/3 of the rest on a t-shirt he then spent the remai

ning money on some CDs what fraction of the money was spent on CDs show your work

2 answers:

Marat540 [252]3 years ago

8 0

They need to be like terms (so change the denominators into things that match)
<u>1 </u>x3 = <u>3</u>
4 x3 = 12

<u>1 </u>x4 = <u>4</u>
3 x4 = 12

4/12 + 3/12 = 7/12

So, 7/12 of the money was spent.

attashe74 [19]3 years ago

7 0

7/12........ I hope this is right and hope this will help you :)

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Step-by-step explanation:

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3 years ago

A rancher wants to fence in an area of 1500000 square feet in a rectangular field and then divide it in half with a fence down t

VLD [36.1K]

Answer:

6000 ft

Step-by-step explanation:

Let length of rectangular field=x

Breadth of rectangular field=y

Area of rectangular field= $1500000$ square ft

Area of rectangular field= $l\times b$

Area of rectangular field= $x\time y$

$1500000=xy$

$y=\frac{1500000}{x}$

Fencing used ,P(x)= $x+x+y+y+y=2x+3y$

Substitute the value of y

P(x)= $2x+3(\frac{1500000}{x})$

$P(x)=2x+\frac{4500000}{x}$

Differentiate w.r.t x

$P'(x)=2-\frac{4500000}{x^2}$

Using formula: $\frac{dx^n}{dx}=nx^{n-1}$

$P'(x)=0$

$2-\frac{4500000}{x^2}=0$

$\frac{4500000}{x^2}=2$

$x^2=\frac{4500000}{2}=2250000$

$x=\sqrt{2250000}=1500$

It is always positive because length is always positive.

Again differentiate w.r.t x

$P''(x)=\frac{9000000}{x^3}$

Substitute x=1500

$P''(1500)=\frac{9000000}{(1500)^3}>0$

Hence, fencing is minimum at x=1 500

Substitute x=1 500

$y=\frac{1500000}{1500}=1000$

Length of rectangular field=1500 ft

Breadth of rectangular field=1000 ft

Substitute the values

Shortest length of fence used= $2(1500)+3(1000)=6000 ft$

Hence, the shortest length of fence that the rancher can used=6000 ft

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4 years ago

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Answer:

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<u>Answer-</u>

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