I assumed that 3 households are sampled.
Now, is the number in each of these households equal to 1, 3 and 8 people?
Next, the question says, samples of n=2 are randomly selected (with replacement) from these 3.
So are sample space is
11
13
31
33
18
81
38
88
83
88
This is done 9 times.
Is that how you understand the problem?
When they select the household with only 1 person, the variance is 0
When they select the household with 8 people, they variance will be from a discrete uniform distribution
Similarly for household with 3 individuals.
Hence the relationship between AM and CD is : AM=CD
6 times 12= 72. 72 times 7= 504. 504 square ft.
Use a calculator.
(23/13.8)-18=-16.333=(-16)-(1/3)
Answer:
6t - 3
Step-by-step explanation:
9t - 3t + 2
Combine like terms: 9t - 3t = 6t
so
9t - 3t + 2
= 6t - 3
