All categories

4 years ago

I am stuck today Show your work :)

Mathematics

1 answer:

laila [671]4 years ago

4 0

1.) Class B has a greater score than Class A since B has a greater IGN than A.

2.) Class B is scores are spread out more.

You might be interested in

You have a bag of red, white, and blue marbles. you know there are 11 red, 8 blue, and 3 white marbles in the bag. what's the pr

NemiM [27]

I think it’s 8/22. I’m not sure

4 0

4 years ago

Jasmine wants to use her savings of $1,128 to buy video games and music cds. The total price of the music cd she bought was $72.

Firlakuza [10]

24 video games.

First you subtract $72 from $1,128 then you divide $43 from $1,056 and you get 24.5581395
So the most video games jasmine can buy is 24.

8 0

4 years ago

Read 2 more answers

On a particular day, 112 of 280 passengers on a particular DTW-LAX flight used the e-ticket check-in kiosk to obtain boarding pa

Sonja [21]

Answer:

0.2348 = 23.48% probability that four will have used the e-ticket check-in kiosk to obtain boarding passes.

Step-by-step explanation:

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

Population of 280, which means that $N = 280$

112 use e-ticket check-in kiosk, which means that $k = 112$

Sample of eight passengers means that $n = 8$

Find the approximate hypergeometric probability that four will have used the e-ticket check-in kiosk to obtain boarding passes.

This is P(X = 4). So

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 4) = h(4,280,8,112) = \frac{C_{112,4}*C_{168,4}}{C_{280,4}} = 0.2348$

0.2348 = 23.48% probability that four will have used the e-ticket check-in kiosk to obtain boarding passes.

3 0

3 years ago

NEED HELP PLEASE WHAT IS THE NUMBER IN THE QUESTION MARK

bekas [8.4K]

Answer:

i thing it is 2，if i wrong so sorry

6 0

3 years ago

X = 12 9 6 2/3 help me out please you guys are awesome ^-^

vitfil [10]

the answer is x = 6 2/3

ok done. Thank to me :>

4 0

3 years ago