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lesya692 [45]
2 years ago
6

Chase took a taxi from his house to the airport the taxi company charged a pick up fee $1.20 plus $4.75 Per mile . The total far

e was $48.70 not included the tip
Mathematics
1 answer:
taurus [48]2 years ago
3 0
I believe that the taxi went 10 miles

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What are the factors of 36?
denis23 [38]

Answer:

1, 2, 3, 4, 6, 9, 12, 18, 36

Step-by-step explanation:

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2 years ago
Hich of the following is a true statement about perpendicular lines?
IRISSAK [1]

Answer:

C.

perpendicular lines intersect in at least two points..

ok im not sure sorry

3 0
2 years ago
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Choose the equation of the line that is parallel to the x-axis.
True [87]

Answer:

y = 4

Step-by-step explanation:

y = 4

The line will always go along y = 4 and therefore is parallel to the x axis

7 0
3 years ago
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Complete the square f(x) = x^2 + 4x - 8 <br><br><br> PLZ help me ;c
Semenov [28]
Ok, first group x terms
f(x)=(x²+4x)-8
factor out quadratic coefient (no need but that's the step)
f(x)=1(x²+4x)-8
take 1/2 of the linear coefient and square it
4/2=2, (2)²=4
add positive and negative of it insides the parenthasees
f(x)=1(x²+4x+4-4)-8
factor perfect square
f(x)=1((x+2)²-4)-8
distribute
f(x)=1(x+2)²-4-8
f(x)=1(x+2)²-12
and, now if we wanted to find the x intercepts where f(x)=0 then
0=1(x+2)²-12
12=(x+2)²
+/-2√3=x+2
-2+/-2√3=x

x=-2+2√3 or -2-2√3
that is where the x intercept are

and completed square form is
f(x)=(x+2)²-12
6 0
3 years ago
Can someone help me please
morpeh [17]

Answer:

a_{n} = 12 -3(n-1)

Step-by-step explanation:

a_{1}  = 12\\a_{n}  = a_{n-1} - 3

we have to find formula for nth term of series for this problem

a_{1}  = 12\\a_{2}  = a_{2-1} - 3 = a_{1}  -3 =  12 -3 = 9\\a_{3}  = a_{3-1} - 3 = a_{2}  -3 =  9 -3 = 6

Thus, we see series is 12, 9 ,6

Thus, we can see that series is decreasing by unit of 3.

and we know that when there is in increase or decrease in series by a a constant number then series is arithmetic progression series.

Hence, this is a decreasing AP series

In AP

nth term is given

nth term = a+(n-1)d

where a is the first term

d is the common difference

common difference is given by = nth term - (n-)th term

lets take 2nd and 1st term to get common difference.

d = 9-12 = -3

(note: this was obvious by looking at series itself that d is -3 as series was decreasing by 3 unit)

a = 12

thus, nth term = a +(n-1)d

nth term = 12 +(n-1)(-3)

nth term = 12 -3(n-1)

writing this in form of a_{n}

a_{n} = 12 -3(n-1)  Answer

5 0
3 years ago
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