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Rus_ich [418]
3 years ago
7

What is 4/7 times 5/p

Mathematics
1 answer:
Phantasy [73]3 years ago
6 0

Answer:

 p = 35/4 = 8.750

Step-by-step explanation:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

4/7-(5/p)=0

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Considering the expression x/2 + y2. Which statements are true?Mark all that apply.
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Answer:

  D.  8/2 +(-10)² = 104

Step-by-step explanation:

To find which statements are true, evaluate the expression for the given variable values. You do this by putting the numbers in place of the respective variables, then doing the arithmetic.

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  A 83 ≠ 37 . . . . (4/2) +9² = 2 +81 = 83

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  C 52 ≠ 61

  D 104 =104 . . . . true statement

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3 years ago
I guess I'm lacking in differential equations. I couldn't solve this question. Can you help me?
Sonja [21]

Answer:

See Explanation.

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Equality Properties
  • Reciprocals

<u>Algebra II</u>

  • Log/Ln Property: ln(\frac{a}{b} ) = ln(a) - ln(b)

<u>Calculus</u>

Derivatives

Basic Power Rule:

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

Chain Rule: \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)

Derivative of Ln: \frac{d}{dx} [ln(u)] = \frac{u'}{u}

Step-by-step explanation:

<u>Step 1: Define</u>

ln(\frac{2x-1}{x-1} )=t

<u>Step 2: Differentiate</u>

  1. Rewrite:                                                                                                         t = ln(\frac{2x-1}{x-1})
  2. Rewrite [Ln Properties]:                                                                                 t = ln(2x-1) - ln(x - 1)
  3. Differentiate [Ln/Chain Rule/Basic Power Rule]:                                         \frac{dt}{dx} = \frac{1}{2x-1} \cdot 2 - \frac{1}{x-1} \cdot 1
  4. Simplify:                                                                                                          \frac{dt}{dx} = \frac{2}{2x-1} - \frac{1}{x-1}
  5. Rewrite:                                                                                                          \frac{dt}{dx} = \frac{2(x-1)}{(2x-1)(x-1)} - \frac{2x-1}{(2x-1)(x-1)}
  6. Combine:                                                                                                       \frac{dt}{dx} = \frac{-1}{(2x-1)(x-1)}
  7. Reciprocate:                                                                                                  \frac{dx}{dt} = -(2x-1)(x-1)
  8. Distribute:                                                                                                         \frac{dx}{dt} = (1-2x)(x-1)
8 0
3 years ago
Read 2 more answers
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