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hodyreva [135]
4 years ago
13

The distance between Lakeview and Sun Valley s 89 km. About how far is this in miles

Mathematics
1 answer:
saw5 [17]4 years ago
6 0
59.302 miles from Lakeview to Sun Valley
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The answer is B because the LCM of 8 and 9 is 72, which changes 4 5/8 to 4 45/72 and 2 2/9 to 2 16/72. 45/72+16/72 is 61/72 and then add the whole numbers.
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Which of the following represents the zeros of f(x) = x3 − 12x2 + 47x − 60
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F(x) = x • 3 • 2 + 47x - 60
fx =3x - 24x + 47x - 60
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Which of the following is a rational number?
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The data show the average monthly temperatures for two cities over a 6-month period. City 1: {20, 24, 40, 63, 76, 89} City 2: {4
Mrac [35]

Answer:

The MAD of city 2 is <u>less than</u> the MAD for city 1, which means the average monthly temperature of city 2 vary <u>less than</u> the average monthly temperatures for City 1.

Step-by-step explanation:

For comparing the mean absolute deviations of both data sets we have to calculate the mean absolute deviation for both data sets first,

So for city 1:

Mean = x1 = \frac{20+24+40+63+76+89}{6}

x1 = \frac{312}{6}

x1 = 52

Now to calculate the mean deviations mean will be subtracted from each data value. (Note: The minus sign is ignored as the deviation is the distance of value from the mean and it cannot be negative. For this purpose absolute is used)

20-52 = -32=32\\24-52=-28=28\\40-52=-12=12\\63-52=11\\76-52=24\\89-52=37

The deviations will be added then.Mean Absolute Deviation = \frac{32+28+12+11+24+37}{6} \\=\frac{144}{6}\\=24

So the mean absolute deviation for city 1 is 24 ..

For city 2:

Mean = x2 = \frac{41+50+58+62+72+83}{6}

x2 = \frac{366}{6}

x2 = 61

Now to calculate the mean deviations mean will be subtracted from each data value. (Note: The minus sign is ignored)

41-61=-20=20\\50-61=-11=11\\58-61=-3=3\\62-61=1\\72-61=11\\83-61=22

The deviations will be added then.Mean Absolute Deviation = \frac{20+11+3+1+11+22}{6} \\=\frac{68}{6}\\=11.33

So the MAD for city 2 is 11.33 ..

So,

The MAD of city 2 is <u>less than</u> the MAD for city 1, which means the average monthly temperature of city 2 vary <u>less than</u> the average monthly temperatures for City 1.

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3 years ago
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(3x^3)( 1/9x^2 - 6 + 2x)
Veseljchak [2.6K]

Answer:

Step-by-step explanation:

3x^3(1/9x^2-6+2x)

This question is not clear, we can not different between the numerator or denominator of some variable.

3x^3×1/9x^2-3x^3×-6+3x^3×2x

1/3x^(3+2)-18x^3+6x^(3+1)

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