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3 years ago

Would you please help me to solve this 9.1x10^-5)^-4

Mathematics

1 answer:

kap26 [50]3 years ago

7 0

[( 91 * 10^-1 ) *10^ -5]^-4 = (91 * 10^-6)^-4 = 91^-4 * 10^24 = ( 10^24 )/ ( 91^4 ) =
10000000 ≈ 1458258211769

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How is 10 2/3 written as a decimal to the nearest hundred

expeople1 [14]

Answer:

10.67

Step-by-step explanation:

The 10 stays as it is. The 2/3 is approximated by 0.67 (to the nearest hundredth). Thus, we have 10.67 to the nearest hundredth.

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3 years ago

Our current equation is:

inessss [21]

Answer:

Step-by-step explanation:

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3 years ago

State restrictions for the given equation below

Genrish500 [490]

The restriction of the given equation is $cos^{2}x =cos^{2} x$ , other than 0≤x≤2π.

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1 year ago

4 sisters share 3 muffins equally how much does each get

Allushta [10]

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3 years ago

Read 2 more answers

HELP PLEASE 21 POINTS PLEASE HELP ME!!!! <3

Anna007 [38]

n 1 2 3 4 5 6

f(n) 1033 932 831 730 629 528

First term (a₁): 1033 Common difference (d): -101

Explicit rule: $a_{n} = 1134 - 101n$ Recursive rule: $a_{n} = a_{n-1} - 101$

$a_{n} = a_{1} + d(n - 1)$

$a_{n} = 1033 - 101(n - 1)$

$a_{n} = 1033 - 101n + 101$

$a_{n} = 1134 - 101n$

***********************************************************************************

n 1 2 3 4 5 6

f(n) -39 -29 -19 -9 9 19

First term (a₁): -39 Common difference (d): +10

Explicit rule: $a_{n} = -49 + 10n$ Recursive rule: $a_{n} = a_{n-1} + 10$

$a_{n} = a_{1} + d(n - 1)$

$a_{n} = -39 + 10(n - 1)$

$a_{n} = -39 + 10n - 10$

$a_{n} = -49 + 10n$

***********************************************************************************

n 1 2 3 4 5 6

f(n) 3.75 2.5 1.25 0 -1.25 -2.5

First term (a₁): 3.75 Common difference (d): -1.25

Explicit rule: $a_{n} = 5 - 1.25n$ Recursive rule: $a_{n} = a_{n-1} - 1.25$

$a_{n} = a_{1} + d(n - 1)$

$a_{n} = 3.75 - 1.25(n - 1)$

$a_{n} = 3.75 - 1.25n + 1.25$

$a_{n} = 5 - 1.25n$

6 0

3 years ago