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andrezito [222]
3 years ago
9

Is a horizontal line a function? Like y=7.

Mathematics
1 answer:
Sonja [21]3 years ago
3 0

let's recall the vertical line test, <u>for a function, if we run a vertical line anywhere it, it'll touch it only once</u>.  is that true for a horizontal line? yeap.

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What the slope (0,7) and (2,4)​
vodka [1.7K]

Answer: -3/2

Step-by-step explanation:

m= y2-y2 over x2-x1

4-7 over 2-0 is m= -3/2

Hope this helps!  :)

6 0
3 years ago
the legs of an isosceles right triangle each measure 10 inches what is the length of the hypotenuse of this triangle to the near
k0ka [10]
Use the Pythagorean theorem:
(\hbox{leg})^2+(\hbox{leg})^2=(\hbox{hypotenuse})^2 \\&#10;10^2+10^2=x^2 \\&#10;100+100=x^2 \\&#10;x^2=200 \\&#10;x=\sqrt{200} \\&#10;x \approx 14.1

The length of the hypotenuse is approximately 14.1 in.
4 0
3 years ago
2. A function g(x) is defined by the diagram shown below.
skad [1K]

Answer:

Step-by-step explanation:

diagram attached represents a function g(x).

Circle (1) (circle on the left) represents the set of domain (input values) and circle (2) represents the range (output values).

a). For input value x = 7, out put value of the function is y = 9.

   Therefore, g(7) = 9 will be the answer.

b). Range of the function g(x) is the set of output values.

    Range: {12, 9, 9, 17}

c). Inverse of the function g(x) will have,

   Domain: {12, 9, 9, 17}

   Range: {4, 7, 10, 15}

   For input value of x = 9, there are two output values y = 7, 10.

   Since, "a function can't have two output values for the same input value".

   Therefore, inverse of the function g(x) will not represent a function.

8 0
4 years ago
The dot plot shows the number of hours that students spent watching TV.
STALIN [3.7K]

Answer:

B C and D

Step-by-step explanation:

common sense

5 0
3 years ago
The fraction a/b is in simplest terms and equal to the following:((2020^3)-1)/((2021^3)+1) . What is a + b?
blagie [28]

Consider the expression

\dfrac{x^3-1}{(x+1)^3+1}

Factorize the numerator and denominator a difference/sum of cubes:

\dfrac{(x-1)(x^2+x+1)}{((x+1)+1)((x+1)^2-(x+1)+1)}

Expand the denominator:

\dfrac{(x-1)(x^2+x+1)}{(x+2)((x^2+2x+1)-(x+1)+1)}=\dfrac{(x-1)(x^2+x+1)}{(x+2)(x^2+x+1)}=\dfrac{x-1}{x+2}

since <em>x</em> = 2020, and clearly 2020² + 2020 + 1 ≠ 0, so we can cancel the factor of <em>x</em> ² + <em>x</em> + 1. This leaves us with

\dfrac{2020^3-1}{2021^3+1} = \dfrac{2020-1}{2020+2} = \dfrac{2019}{2022}=\dfrac{673}{674}=\dfrac ab

so that <em>a</em> + <em>b</em> = 673 + 674 = 1347.

7 0
3 years ago
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