Answer:
44x + 54
Step-by-step explanation:
The nth term of an arithmetic sequence is given by :
Tn = a + (n - 1)d
d = common difference = T2 - T1
d = T2 - T1
a = first term = - x + 9
d = 4x + 14 - (-x + 9)
d = 4x + 14 + x - 9
d = 5x + 5
The 10th term:
T(10) = (-x + 9) + (10 - 1)*(5x + 5)
T(10) = - x + 9 + 9(5x + 5)
T(10) = - x + 9 + 45x + 45
T(10) = 44x + 54
Hence, the 10th term is 44x + 54
8 and 0
Hopefully this helps you
I=prt,,262.5=3000*3.5 r,,r=262.5/3000*3.5= use the calculator
Let p (x) = 4x^4-13x^2-2x
The zero of x-2 is 2
putting x = 2 in p (x), we get,
p (2) = 4×2^4-13×2^2-2×2
= 64 - 52 - 4
= 64 - 56
= 8
Therefore, remainder = 8
Answer:
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