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Nonamiya [84]
3 years ago
10

Use substitution to find the solution to the system of equations.

Mathematics
2 answers:
Mariana [72]3 years ago
7 0

Answer:

A. (-3,-2)

Step-by-step explanation:

In substitution method for solving a system of equation we find the value of a variable from one equation and put it into the other equation.

Here, the given system of equation,

5x+7y=-29  ----(1)

y=x+1 -----(2),

Substitute the value of y from equation (2) to equation (1),

5x + 7(x+1) = -29

5x + 7x + 7 = -29

12x + 7 = -29

12x = -36

x = -3

From equation (2),

y = -3 + 1 = -2

Hence, the solution of the given system is ( -3, -2 )

Option A is correct.

mote1985 [20]3 years ago
4 0

Answer:

Ummm, so the answer is A. (-3,-2)

StepByStep Solution:

5x + 7(x+1) =-29

5x+7x+7=-29

12x=-36

x=-3

y=-3+1

y=-2

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A bird (b) is spotted flying 900 feet from an observer. the observer (o) also spots the top of a tower (t) at a height of 200 fe
Svetach [21]

Angle of depression = 12.52°

The right angle triangle formed has a height of 200 ft and a base of 900 ft.

The opposite side of the triangle is 200 ft while the adjacent side of the triangle is 900 ft.

Using tangential ratio we can find the angle of depression. Therefore,

Let

x = angle of depression

tan x = opposite/adjacent

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adjacent = 900 ft

tan x = 200/900

tan x = 2/9

x = tan⁻¹ 2/9

x = tan⁻¹ 0.222

x = 12.5166739144

x = 12.52°

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2 years ago
I will give brainliest<br>Help me
r-ruslan [8.4K]

Answer:

See Explanation

Step-by-step explanation:

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6 0
3 years ago
Write 9x² - 36x = 4y² + 24y + 36 in standard form
Kisachek [45]

Answer:

9·x² - 36·x = 4·y² + 24·y + 36 in standard form is;

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Step-by-step explanation:

The standard form of a hyperbola is given as follows;

(x - h)²/a² - (y - k)²/b² = 1 or (y - k)²/b² - (x - h)²/a² = 1

The given equation is presented as follows;

9·x² - 36·x = 4·y² + 24·y + 36

By completing the square, we get;

(3·x - 6)·(3·x - 6) - 36 = (2·y + 6)·(2·y + 6)

(3·x - 6)² - 36 = (2·y + 6)²

(3·x - 6)² - (2·y + 6)² = 36

(3·x - 6)²/36 - (2·y + 6)²/36 = 36/36 = 1

(3·x - 6)²/6² - (2·y + 6)²/6² = 1

3²·(x - 2)²/6² - 2²·(y + 3)²/6² = 1

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The equation of the hyperbola  is (x - 2)²/2² - (y + 3)²/3² = 1.

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-18 &gt; |-1 (3-2x)| &gt; 18
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Answer:

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Step-by-step explanation:

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